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BaLLatris [955]
3 years ago
13

The volleyball team practiced their serves, rotations, and ________. Which choice completes the sentence with correct parallel s

tructure?
a. spikes.
b. spiking.
c. spikes the ball.
d. spikes over the net.
Physics
2 answers:
Phoenix [80]3 years ago
5 0

Answer

Correct Answer is a.(spikes)

Explanation:

option a is correct because here serves, rotation and spikes all the three words are using as object.

The volleyball team practiced their serves, rotations, and spikes.

option b cannot be correct because here spiking is used as a verb and sentence(The volleyball team practiced their serves, ) is in past indefinite form and we cant use word spiking here because this form of verb is used in continues form of sentences only.

Option c cannot be correct as because in this option ""spikes the ball" spikes is used as a verb  which can be used in present indefinite form of sentence only but here sentence is in past indefinite form.

Again option d cannot be correct because  in this option ""spikes over the net" spikes is used as a verb  which can be used in present indefinite form of sentence only but here sentence is in past indefinite form.

pychu [463]3 years ago
3 0

Answer:

Option (A)

Explanation:

Parallel structure in a sentence refers to the usage of the same type of words that describes multiple purposes comprised of equal significance. These parallel structures are usually connected in a sentence by using coordinating conjunctions. For example, and, or.

In the given question, the correct answer is "spikes" that completes the above sentence with the correct parallel structure.

A volleyball spike is defined as a game-plan that is usually set by the team players, where the ball is to pass through over the net in such a way that nobody in the opposite team can receive the ball, thereby adding points to the team that throws the ball. In order to do this, a good practice is required by the players.

Thus, the correct answer is option (A).

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Answer:

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Explanation:

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3 years ago
What is keeping all variables the same except for the one being tested an example of?
stepan [7]

Answer:

A fair test.

Explanation:

Hi, a fair test is used to do scientifically valuable experiments, is a controlled investigation to answer a scientific question.

In a fair test two or more things are compared.

It consists in changing only one factor (the one bieng tested) and keeping all the other conditions the same during an experiment.

The factor is called a variable.

8 0
3 years ago
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Newton's first law of motion states that an object will keep a constant speed and direction unless acted upon by an unbalanced f
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Answer:

The unbalanced force that caused the ball to stop was friction

Explanation:

As Newton's second law states, the acceleration of an object is proportional to the net force applied on the object:

F=ma

therefore, in order to move at constant speed, an object should have a net force of zero (balanced forces) acting on it.

In this case, the ball slows down and eventually comes to a stop: it means that the ball is decelerating, so there are unbalanced forces (net force different from zero) acting on it. The unbalanced force acting on the ball is the friction: friction is a force against the motion of the object, which is due to the contact between the surface of the ball and the surface of the street, and this force is responsible for slowing down the ball.

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3 years ago
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A constant force of 45 N directed at angle θ to the horizontal pulls a crate of weight 100 N from one end of a room to another a
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Answer:

W=173.48J

Explanation:

information we know:

Total force: F=45N

Weight: w=100N

distance: 4m

vertical component of the force: F_{y}=12N

-------------

In this case we need the formulas to calculate the components of the force (because to calculate the work we need the horizontal component of the force).

horizontal component: F_{x}=Fcos\theta

vertical component: F_{y}=Fsen\theta

but from the given information we know that F_{y}=12N

so, equation these two F_{y}=Fsen\theta and F_{y}=12N

Fsen\theta =12N

and we know the force F=45N, thus:

45sen\theta=12

now we clear for \theta

sen\theta =12/45\\\theta=sin^{-1}(12/45)\\\theta =15.466

the angle to the horizontal is 15.466°, with this information we can calculate the horizontal component of the force:

F_{x}=Fcos\theta

F_{x}=45cos(15.466)\\F_{x}=43.37N

whith this horizontal component we calculate the work to move the crate a distance of 4 m:

W=F_{x}*D\\W=(43.37N)(4m)\\W=173.48J

the work done is W=173.48J

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