Answer:
D
Explanation:
The density has a formula of d = m / V.
The volumes are given as the same.
The density will be
d_lead = 113/ V
d_aluminum = 27/V
It does not matter for this question what the volume actually is. Just note that the value of the volume is the same for each ball.
A: incorrect. If the volumes are the same, the density is not the same because the masses are different.
B: incorrect. If the density of the two balls was less than water, the two balls would float. Never going to happen unless the balls are thin shells.
C: incorrect. The exact opposite is the answer.
D: Correct. This is the answer.
Answer:
891 excess electrons must be present on each sphere
Explanation:
One Charge = q1 = q
Force = F = 4.57*10^-21 N
Other charge = q2 =q
Distance = r = 20 cm = 0.2 m
permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)
Using Coulomb's law,
F=[1/4pieo]q1q2/r^2
F = [1/4pieo]q^2 / r^2
q^2 =F [4pieo]r^2
q = r*sq rt F[4pieo]
q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]
q = 1.42614*10^ -16 C
number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19
n =891
891 excess electrons must be present on each sphere
Based on your question the answer to this is the following and i hope i answered you question correctly:
How much energy is transferred to her eardrums each second ?
-6.31
<span>
How fast would a 2.00 mg mosquito have to fly to have this much kinetic energy? </span>
-1.39*10^-5<span>
How fast a typical 2.0 mg mosquito would have to fly (in mm/s) to have an amount of energy delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear?
-</span><span>3.5 joules</span>
Answer:
Explanation:
Given;
The operational pressure of the cooker, 
area of the opening, 
- We know that the gauge pressure is measured with respect to the atmospheric pressure. As the atmospheric pressure acts on all the components of the system being observed so, we only need to counter the gauge pressure.
As the petcock sits on the opening of the cross-section so, it balances the built-in pressure due to its weight.
<u>Hence:</u>
where:
mass of the petcock
acceleration due to gravity
Answer:
The correct answer is the sea
