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Simora [160]
3 years ago
15

A 400-turn circular coil (radius = 1.0 cm) is oriented with its plane perpendicular to a uniform magnetic field which has a magn

itude that varies sinusoidally with a frequency of 90 Hz. If the maximum value of the induced emf in the coil is observed to be 4.2 V, what is the maximum value of the magnitude of the varying magne?
Physics
1 answer:
kaheart [24]3 years ago
4 0

Answer:

The Magnetic field is 59.13 mT.

Explanation:

Given that,

Number of turns = 400

Radius = 1.0 cm

Frequency = 90 Hz

Emf = 4.2 V

We need to calculate the angular velocity

Using formula of angular velocity

\omega=2\pi f

\omega=2\times3.14\times90

\omega=565.2\ rad/s

We need to calculate the magnetic flux

Relation between magnetic flux and induced emf

\epsilon=NA\omega B

B=\dfrac{\epsilon}{NA\omega}

Put the value into the formula

B=\dfrac{4.2}{400\times\pi\times(1.0\times10^{-2})^2\times 565.2}

B=0.05913\ T

B=59.13\ mT

Hence, The Magnetic field is 59.13 mT.

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Answer:

a) Indeed, the linear speed of the ultracentrifuge is 0.524 kilometers per second.

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Explanation:

The linear speed of the particle (v), measured in kilometers per second, rotating in a circular pattern is calculated by the following formula:

v = R\cdot \omega (1)

Where:

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\omega - Angular speed, measured in radians per second.

Now we proceed to calculate the linear speed of each element:

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If we know that \omega \approx 5235.988\,\frac{rad}{s} and R = 1\times 10^{-4}\,km, then the linear velocity is:

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Indeed, the linear speed of the ultracentrifuge is 0.524 kilometers per second.

b) Earth

The Earth is 150 million kilometers away from the Sun and takes 365 days to complete one revolution around the Sun. First, we calculate angular speed of the planet:

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If we know that T = 31536000\,s, then the angular speed of the Earth is:

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