Answer:
- The magnitude of the vector
is 107.76 m
Explanation:
To find the components of the vectors we can use:

where
is the magnitude of the vector, and θ is the angle over the positive x axis.
The negative x axis is displaced 180 ° over the positive x axis, so, we can take:






Now, we can perform vector addition. Taking two vectors, the vector addition is performed:

So, for our vectors:


To find the magnitude of this vector, we can use the Pythagorean Theorem



And this is the magnitude we are looking for.
Answer:
The term mass is used to refer to the amount of matter in any given object For instance, a person or object may be weightless on the moon because of the lack of gravity but that same person or object maintains the same mass regardless of location
Explanation:
Answer:
a) 1.22 s
b) 9.089 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²

Time taken by the ball to reach the highest point is 1.22 seconds

The maximum height the ball will reach above the ground is 1.75+7.339 = 9.089 m
Answer:
Magnitude the net torque about its axis of rotation is 1.3338 Nm
Explanation:
The radius of the wrapped rope around the drum, r = 1.24 m
Force applied to the right side of the drum, F = 4.56 N
The radius of the rope wrapped around the core, r' = 0.57 m
Force on the cylinder in the downward direction, F' = 7.58 N
Now, the magnitude of the net torque is given by:

where
= Torque due to Force, F
= Torque due to Force, F'

Now,

The net torque comes out to be negative, this shows that rotation of cylinder is in the clockwise direction from its stationary position.
Now, the magnitude of the net torque:
