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stira [4]
3 years ago
6

X-rays cannot pass through Earth's atmosphere. Which of these is the best location to place a telescope used to observe x-rays f

rom stars?
mountain
top of building
space
high-flying aircraft
Physics
2 answers:
Amiraneli [1.4K]3 years ago
7 0
Mountains, tops of buildings, and high-flying aircraft are all part of Earth's atmosphere, no matter how high they are. On the other hand, space doesn't belong to our atmosphere, it is outside of it. Having this in mind, the best location to place a telescope used to observe x-rays from stars is in space.
VashaNatasha [74]3 years ago
4 0
Space because you are closest to the stars
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Answer:

28.8 meters

Explanation:

We must first determine at which velocity the ball hits the water. To do so we will:

1) Assume no air resistance.

2) Use the Law of conservation of mechanical energy: E=K+P

Where

E is the mechanical energy (which is constant)

K is the kinetic energy.

P is the potential energy.

With this we have \frac{m}{2} *v^{2}  = m*g*h

Where:

m is the balls's mass <- we will see that it cancels out and as such we don't need to know it.

v is the speed when it hits the water.

g is the gravitational constant (we will assume g=9.8\frac{m}{s^{2} }.

h is the height from which the ball fell.

Because when we initially drop the ball, all its energy is potential (and P = - m*g*h) and when it hits the water, all its energy is kinetic (K=\frac{m}{2} *v^{2}. And all that potential was converted to kinetic energy.

Now, from \frac{m}{2} *v^{2}  = m*g*h we can deduce that v=\sqrt{2*g*h}

Therefore v=9.6\frac{m}{s}

Now, to answer how deep is the lake we just need to multiply that speed by the time it took the ball to reach the bottom.

So D=9.6\frac{m}{s}*3s=28.8m

Which is our answer.

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