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3 years ago

9

Under what environmental conditions are you most likely to generate static electricity?

1 answer:

pogonyaev3 years ago

5 0

Mostly when your around carpet or anything related to a carpet because when you do it long enough you will generate static electricity i hope this helps

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Why is it recommended that windows face north in Alice Springs, Australia for passive solar heating?

ladessa [460]

The Passive solar heating uses free free heating direct from the sun to reduce the estimated forty percent of energy consumed in the average australian home for space heating and cooling. many heating and cooling design objectives overlap but different emphasis is required depends on your climate need.

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3 years ago

Reviewing old tests and quizzes will not help you determine what will be on a test because teachers don’t like to give students

kifflom [539]

Answer:

False

Explanation:

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4 years ago

Read 2 more answers

Light propagating in air strikes the surface of a lake. The reflected ray makes 62° angle with the normal. What angle does the r

blondinia [14]

Answer:

(a) 42°

Explanation:

According to the law of reflection:

Angle of incidence = Angle of reflection

So, angle of reflection = 62°

Angle of incidence = 62°

For refraction,

Using Snell's law as:

$n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence ( 62.0° )

${\theta_r}$ is the angle of refraction ( ? )

${n_r}$ is the refractive index of the refraction medium (water, n=1.33)

${n_i}$ is the refractive index of the incidence medium (air, n=1)

Hence,

$1\times {sin62.0^0}={1.33}\times{sin\theta_r}$

Angle of refraction = $sin^{-1}0.6639$ = 42°

4 0

3 years ago

Plzz answer this correctly

AysviL [449]

Answer:

C and E...................

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3 years ago

What is the wavelength of the third harmonic in a 4.5-m-long pipe that is closed at one end?

lisov135 [29]

Answer:

Wavelength of sound in the pipe is 6.0 m

Explanation:

As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node

Here we know that in closed pipes on odd harmonics will exist

so here for third harmonic we have

$L = \frac{\lambda}{4} + \frac{\lambda}{2}$

where L = length of the pipe

so we have

$4.5 = \frac{3\lambda}{4}$

$\lambda = 6.0 m$

5 0

3 years ago