Ask question

Ask question

All categories

3 years ago

14

SCIENCE

1 answer:

aivan3 [116]3 years ago

7 0

Answer:

c is trueeeeeeeeeeeeeee

You might be interested in

60 POINTS model how sound produced by a singer is recorded by a microphone and reproduced by a speaker (sound model) WITH RUBIC

Nikolay [14]

Answer:

Explanation: i don't know bro

6 0

2 years ago

Lol i'm going to fail please help

Novosadov [1.4K]

Answer:

Explanation:

The frequency is 16.0 Hz. That means that 16 of these waves can pass a single point in 1 second. We are given frequency and wavelength. The equation that relates them is

$f=\frac{v}{\lambda}$ where f is frequency, v is velocity, and λ is wavelength. Putting all this together:

$16.0=\frac{v}{97.5}$ and solving for velocity,

v = 16.0(97.5) so

v = 1560 m/s. This wave can travel 1560 meters in a single second!!! Now that we know this velocity, we can use it in a proportion to find our unknown, which is how long, t, it will take to hear this sound 11000m away. (11 km is 11000m):

$\frac{1560m}{1s}=\frac{11000}{t}$ and cross multiply to get

1560t = 11000 so

t = 7.1 seconds

6 0

3 years ago

A rock is dropped from a height of 3,245 m. If we ignore air resistance, how fast will it be travelling after it falls for 3.4 s

Marta_Voda [28]

Answer:

<u>954.4m/s</u>

Explanation:

For a free falling object,it has constant acceleration and a changing velocity.

By using the velocity-time formula, the velocity can be obtained.

The height the rock travelled is the distance.

From,

Velocity (v) = Distance (d) / Time(t)

v = 3245m/3.4s

v = <u>954.4m/s</u>

That js the answer I got. Hope it's right.

3 0

3 years ago

How does the intensity of a sound wave change if the distance from the

Alex17521 [72]

Answer:

The new intensity decreases by a factor of 16.

Explanation:

The intensity of sound wave is given by :

$I=\dfrac{P}{A}$

P is power

A is area

$I=\dfrac{P}{4\pi r^2}$

or

$I\propto \dfrac{1}{r^2}$ , r is distance from the source

If the distance from the source is increased by a factor of 4, r' = 4r

So,

$I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}$

So, the new intensity decreases by a factor of 16.

8 0

3 years ago

A solid weight 277.5g in air and 212.5g when totally immersed in the liquid of density 0.9 g/cm³.Calculate the density of solid.

Gre4nikov [31]

Explanation:

Here is the answer,

Lets be BF

4 0

3 years ago

Read 2 more answers