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2 years ago

The pH of a solution changes from 3.00 to 6.00. By what factor does the [H3O+] change?

Chemistry

2 answers:

PSYCHO15rus [73]2 years ago

8 0

Answer: $10^3$

Explanation:-

pH is the measure of acidity or alkalinity. It is also defined as negative logarithm of hydrogen ion concentration.

$pH=-log[H_3O^+]$

Given: $pH$ = 3

Thus $3=-log[H_3O^+]$

$[H_1^+]=10^{-3}$

$6=-log[H_3O^+]$

$[H_3O^+]=10^{-6}$

$\frac{10^{-3}}{10^{-6}}=10^3$

Thus $H_3O^+$ changes by $10^3$ units.

Naya [18.7K]2 years ago

4 0

: E) 1000 = 10^3
6-3 = 3 ==> change is 10^3
HOPE I COULD HELP

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torisob [31]

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zavuch27 [327]

$F^{-}$ is most abundant and 6310 times more than HF.

<h3>What is a strong and weak acid?</h3>

When an acid is dissolved in water, all of its molecules disintegrate, making the acid powerful.

When an acid is dissolved in water, only a small number of its molecules disintegrate, making the acid weak. Strong acids have a lower pH than weak acids.

The powerful acids include perchloric acid, chloric acid, nitric acid, sulfuric acid, hydrobromic acid, and hydroiodic acid.

Given:

Pka=3..2

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Let the volume be 1 liter

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$pH=pka+log \frac{F^{-}}{HF} \\\\7=3.2+log\frac{F^{-}}{HF} \\3.8=log\frac{F^{-}}{HF}\\ \frac{F^{-}}{0.1}=10^{3.8} \\F^{-}=630.95 M$

Now,

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1 year ago

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A divalent anion is an atom that has gained two electrons. Such anion has 2 negative charge. Thus, divalent Y would be $Y^2^-$

Since Y is a divalent anion, it requires 2 electrons in order to successfully bind with another charged atom, a cation to be specific. Thus, two of $X^+$ would be required to successfully bind $Y^2^-$

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Answer:

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