To find for the oxidizing agent, first let us write the
half reactions of this complete chemical reaction:
Ca = Ca2+ + 2e- <span>
2 H+ + 2e- = H2</span>
The oxidizing agent
would be the substance of the element that is reduced. We know that an element
is reduced when an electron is added to it. In this case, the element being
reduced is H. Therefore the oxidizing agent is HNO3.
Answer:
<span>HNO3</span>
Answer:
A
Explanation:
i had to answer this question a few weeks ago
PH scale is used to determine how acidic , basic or neutral a solution is. It can be calculated using the following equation
pH = -log [H₃O⁺]
hydronium ion concentration has already been given
[H₃O⁺] = 4.91 x 10⁻⁴ M
pH = -log[4.91 x 10⁻⁴ M]
pH = 3.3
the pH of medium is 3.3
Answer: Pb(NO3)2(aq) + 2KI(aq) —> PbI2(s) + 2KNO3(aq)
1.57x10^22 atoms of Pb
87% yield
Explanation:
10.0 g Pb(II) nitrate = 10/333 moles = 0.03 moles
12.0 g KI = 12/166 moles = 0.072 moles (0.06 moles required)
11.4 g PbI2 = 11.4/421 moles = 0.026 moles
expected yield 0.03 moles, yield = 87%
atoms in 11.4 g = 0.026 moles = 0.026*6.02214076*10^23 atoms = 1.57*10^22