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3 years ago

what was the mass of a cannkn ball whose velocity is 200m/s if it were shot from 1000kg that recoils a 2m/s. Solve step by step

1 answer:

6 0

The famous Newton’s Third Law states that “For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.”

By using this,

10grams or 0.01kg of bullet with speed 400 m/sec and 5kg gun recoil with speed suppose ‘v’.

0.01×400=5×v

4/5=v

v=0.8m/sec ANSWER.

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A moving object has a kinetic energy of 150J and a momentum of 20.3kgxm/s find the speed of the object in m/s

Irina-Kira [14]

Answer:

$v = 14.78m/s$

Explanation:

Given

$KE = 150J$

$p = 20.3kgm/s$

Required

Determine the object's speed

Kinetic Energy is calculated as:

$KE = \frac{1}{2}mv^2$

Make m the subject

$m = \frac{2KE}{v^2}$

Momentum is calculated as:

$p = mv$

Make m the subject

$m = \frac{p}{v}$

So, we have:

$m = \frac{p}{v}$ and $m = \frac{2KE}{v^2}$

Equate both expressions: $m = m$

$\frac{2KE}{v^2} = \frac{p}{v}$

Multiply both sides by v

$v * \frac{2KE}{v^2} = \frac{p}{v}*v$

$\frac{2KE}{v} = p$

Make v the subject

$v = \frac{2KE}{p}$

Substitute $KE = 150J$ and $p = 20.3kgm/s$

$v = \frac{2 * 150}{20.3}$

$v = \frac{300}{20.3}$

$v = 14.78m/s$

5 0

3 years ago

In an electromagnetic wave in free space, the electric and magnetic fields are.

Vlad [161]

Answer:

PERPENDICULAR

Explanation:

<h3>HOPE IT HELPS </h3>

6 0

2 years ago

In the Bohr model of the atom, atomic electrons approximatately 'orbit' the nucleus. The hydrogen atom consists of a proton of m

lara31 [8.8K]

Answer:

$F=3.61\times 10^{-47}\ N$

Explanation:

Mass of a proton, $m_p=1.67\times 10^{-27}\ kg$

Mass of an electron, $m_e=9.11\times 10^{-31}\ kg$

The distance between the electron and the proton is, $r=5.3\times 10^{-11}\ m$

We need to find the mutual attractive gravitational force between the electron and proton. The gravitational force is given by :

$F=G\dfrac{m_em_p}{r^2}$

Where G is the universal Gravitational constant

$F=6.67\times 10^{-11}\times \dfrac{9.11\times 10^{-31}\times 1.67\times 10^{-27}}{(5.3\times 10^{-11})^2}\\\\F=3.61\times 10^{-47}\ N$

So, the force between the electron and proton is $3.61\times 10^{-47}\ N$ .

7 0

3 years ago

How does the circuit change when the wire is added? a closed circuit occurs and makes all bulbs turn off. an open circuit occurs

Vitek1552 [10]

The circuit change when a wire is added is, an open circuit occurs and makes all bulbs turn off.

<h3>What is a closed circuit?</h3>

A closed circuit is a type of circuit connection in which the wire connection is complete and current flow occurs, turning the light bulbs on in the process.

<h3>What is an open circuit?</h3>

An open circuit is a type of circuit connection in which the wire connection is incomplete and current cannot flow, turning off the light bulbs.

Thus, the circuit change when the wire is added is, an open circuit occurs and makes all bulbs turn off.

Learn more about open circuit here: brainly.com/question/20351910

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3 0

2 years ago

g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr

Lorico [155]

To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

$a = \frac{GM}{r^2}$