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3 years ago

What is displacement and distance

Physics

1 answer:

iogann1982 [59]3 years ago

7 0

Answer:

Displacement is how far you are between your initial and finishing position.

Distance is how far you went.

Explanation:

For example, using a baseball field... if the sides are each 100 m..

A batter runs to third base... what is his displacement and distance?

Since the batter ran to 3rd base, it means he ran 300 m to get to 3rd base but his displacement is 100 m becuase that's how far they are from home plate. (which was their starting position)

So the answer to my example above would be:

Distance: 300 m

Displacement: 100 m

I hope this helped you.

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True or False <br>One of the objections to the solar nebula theory is the angular momentum problem.

KengaRu [80]

Answer:

False, the angular momentum problem is not one of the objections to the solar nebular theory.

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3 years ago

A person using an oxygen mask is breathing air that is 33% oxygen. what is the partial pressure of the o2, when the air pressure

yawa3891 [41]

The partial pressure of the O2 is 36.3 kiloPascal when the air pressure in the mask is 110 kiloPascal based on the isotherm relation. This problem can be solved by using the isotherm relation equation which stated as Vx/Vtot = px/ptot, where V represents volume, p represents the pressure, x represents the partial gas, and tot represents the total gas<span>. Calculation: 33/100 = px/110 --> px = 36.3</span>

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3 years ago

A small metal bead, labeled A has a charge of 25 nC. It is touched to metal bead B, initially neutral, so that the two beads sha

Iteru [2.4K]

Answer:

15 nC and 10 nC

Explanation:

qA + qB = 25 nC = 25 x 10^-9 C

F = 5.4 x 10^-4 N

d = 5 cm = 0.05 m

Use the Coulomb's law

$F=\frac{Kq_{A}q_{B}}{d^{2}}$

By substituting the values, we get

$5.4 \times 10^{-4}=\frac{9 \times 10^{9}q_{A}q_{B}}{0.05^{2}}$

qA x qB = 1.5 x 10^-16 C

So, $q_{A}\left ( 25 \times 10^{-9}-q_{A} \right )=1.5 \times 10^{-16}$

$q_{A}^{2}-25 \times 10^{-9}q_{A}+1.5 \times 10^{-16}=0$

$q_{A}=\frac{25\times 10^{-9} \pm \sqrt{6.25\times 10^{-16}-6 \times10^{-16}}}{2}$

$q_{A}=\frac {25\times 10^{-9} \pm 5 \times 10^{-9}}}{2}$

qA = 15nC or 10nC

So, qB = 10 nC or 15 nC

8 0

4 years ago

What is the total current I flowing through a system with two resistors in parallel with resistances of 2Ω and 5Ω, and a battery

Andrej [43]

Answer:

Explanation:

Current I = potential difference V ÷ Resistance R

I = V/R ........1

The overall resistance of parallel resistors is;

1/Rt = 1/R1 + 1/R2 ........2

Given;

V = 10V

R1 = 2 ohms

R2 = 5 ohms

Substituting the values into equation 2, to calculate the overall resistance;

1/Rt = 1/2 + 1/5

1/Rt = 7/10

Rt = 10/7 ohms

From equation 1, we can solve for the total current;

I = V/Rt = 10/(10/7)

I = 7A

The total current I flowing through a system is 7A

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4 years ago

Which of these orders has the structure of the universe from the smallest to largest?

Oliga [24]

Answer:

From largest to smallest they are: Universe, galaxy, solar system, star, planet, moon and asteroid.

Explanation:

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2 years ago