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2 years ago

What is displacement and distance

Physics

1 answer:

iogann1982 [59]2 years ago

7 0

Answer:

Displacement is how far you are between your initial and finishing position.

Distance is how far you went.

Explanation:

For example, using a baseball field... if the sides are each 100 m..

A batter runs to third base... what is his displacement and distance?

Since the batter ran to 3rd base, it means he ran 300 m to get to 3rd base but his displacement is 100 m becuase that's how far they are from home plate. (which was their starting position)

So the answer to my example above would be:

Distance: 300 m

Displacement: 100 m

I hope this helped you.

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Vectors a and b have scalar product â6.00, and their vector product has magnitude +9.00. what is the angle between these two vec

salantis [7]

Answer:

Value of angle between vector a and b is $56.30^{\circ}$ .

Explanation:

Vectors a and b have scalar product 6.00

Let $\theta$ be the angle between a and b.

$\vec{a}.\vec{b} = 6$

ab cos $\theta$ = 6 ...(1)

Vectors a and b have magnitude of vector product 9.00

$\vec{a} \times\vec{b} = 9$

ab sin $\theta$ = 9 ...(2)

Dividing equation (2) by (1) we get

$\frac{ab sin \theta}{ab cos \theta} = \frac{9}{6}$

tan $\theta$ = 1.5

$\theta = tan ^{-1} (1.5)$

$\theta$ = $56.30^{\circ}$

Thus, value of angle between vector a and b is $56.30^{\circ}$ .

3 0

3 years ago

Alguien sabe como resolver esto? no entiendo.

lorasvet [3.4K]

Answer:

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Explanation:QCGQ G GQUIGI QGUI; V AYDFYAFQAVAVY,

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2 years ago

A dart is inserted into a spring-loaded dart gun by pushing the spring in by a distance x. For the next loading, the spring is c

bezimeni [28]

Answer:

The second dart leaves the gun two times as faster than the first one.

Explanation:

Assuming no energy loss during the spring-dart energy transfer, we have by the conservation of energy principle

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Given an arbitrary $x$ and its double, $2x$ , launch velocities are

$v_1 = \sqrt{\frac{k}{m}x^2} \text{ and} \\ v_2 = \sqrt{\frac{k}{m}\left(2x\right)^2} = \sqrt{\frac{k}{m}4x^2} = 2\sqrt{\frac{k}{m}x^2} = \mathbf{2v_1}.$