Question

The position of a particle moving along a coordinate line is s equals StartRoot 76 plus 6 t EndRoot​, with s in meters and t in seconds. Find the rate of change of the​ particle's position at t equals 4 sec. The rate of change of the​ particle's position at t equals 4 sec is 104 4 m divided by sec.

Answer 1

Answer:

= 3 /10

Explanation:

s = √(76 + 6t)

ds/dt = $\frac{1}{2} (76 + 6t)^-^(^1^/^2^) . 6$

at t = 4

ds / dt = $\frac{1}{2} (76 + 6(4))^-^(^1^/^2^) . 6$

  = $\frac{1}{2} (100)^-^(^1^/^2^) . 6$

  = 3 / 10