Answer:
Approximately
(assuming that
.)
Explanation:
Let
denote the force that this spring exerts on the object. Let
denote the displacement of this spring from the equilibrium position.
By Hooke's Law, the spring constant
of this spring would ensure that
.
Note that the mass of the object attached to this spring is
. Thus, the weight of this object would be
.
Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus,
.
The spring in this question was stretched downward from its equilibrium by:
.
(Note that
is negative since this displacement points downwards.)
Rearrange Hooke's Law to find
in terms of
and
:
.
De Broglie's identity gives the relationship between the momentum and the wavelength of a particle:

where
p is the particle momentum
m is its mass
v its velocity
h is the Planck constant

is the wavelength
By re-arranging the equation, we get

and by using the data about the proton, given in the text, we can find the proton's wavelength:
Answer:
the answer is B
Explanation:
the law states that for every action there is an equal and opposite reaction. action and reaction forces always act on two two different bodies and therefore THEY ALWAYS EXIST IN PAIRS.
Answer:
6.3445×10⁻¹⁶ m
Explanation:
E = Accelerating voltage = 2.47×10³ V
m = Mass of electron
Distance electron travels = 33.5 cm = 0.335 cm

Deflection by Earth's Gravity

Now, Time = Distance/Velocity

∴ Magnitude of the deflection on the screen caused by the Earth's gravitational field is 6.3445×10⁻¹⁶ m