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Salsk061 [2.6K]
2 years ago
11

You throw a bowling ball down an alley with speed v_0v ​0 ​​ , and initially it slides without rolling. After a little while fri

ction kicks in and the ball begins to roll. What is the speed of the bowling ball when it starts rolling without slipping?
Physics
1 answer:
telo118 [61]2 years ago
4 0

Answer:

final speed after pure rolling is given as R\omega = \frac{5}{7}v_0

Explanation:

As we know that point of contact at ground is taken as reference then there is no external torque about this point on the ball

So we can use angular momentum conservation about this point

L_i = L_f

L_i = mv_0R

L_f = \frac{7}{5}mR^2\omega

so we have

mv_0R = \frac{7}{5}mR^2\omega

R\omega = \frac{5}{7}v_0

So final speed after pure rolling is given as R\omega = \frac{5}{7}v_0

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Explanation:

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A piston-cylinder device initially contains 0.3 kg of nitrogen gas at 160 kPa and 140oC. The nitrogen is now expanded isothermal
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Answer:

<h2>Work done by the gas is given as</h2><h2>W = 1.72 \times 10^4 J</h2>

Explanation:

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