1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Salsk061 [2.6K]
3 years ago
11

You throw a bowling ball down an alley with speed v_0v ​0 ​​ , and initially it slides without rolling. After a little while fri

ction kicks in and the ball begins to roll. What is the speed of the bowling ball when it starts rolling without slipping?
Physics
1 answer:
telo118 [61]3 years ago
4 0

Answer:

final speed after pure rolling is given as R\omega = \frac{5}{7}v_0

Explanation:

As we know that point of contact at ground is taken as reference then there is no external torque about this point on the ball

So we can use angular momentum conservation about this point

L_i = L_f

L_i = mv_0R

L_f = \frac{7}{5}mR^2\omega

so we have

mv_0R = \frac{7}{5}mR^2\omega

R\omega = \frac{5}{7}v_0

So final speed after pure rolling is given as R\omega = \frac{5}{7}v_0

You might be interested in
A 540 gram object is attached to a vertical spring, causing the spring’s length to change from 70 cm to 110 cm.
belka [17]

Answer:

Approximately 13\; {\rm N \cdot m^{-1}} (assuming that g = 9.81\; {\rm N \cdot kg^{-1}}.)

Explanation:

Let F_{\text{s}} denote the force that this spring exerts on the object. Let x denote the displacement of this spring from the equilibrium position.

By Hooke's Law, the spring constant k of this spring would ensure that F_\text{s} = -k\, x.

Note that the mass of the object attached to this spring is m = 540\; {\rm g} = 0.540\; {\rm kg}. Thus, the weight of this object would be m\, g = 0.540\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \approx 5.230\; {\rm N}.

Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, F_{\text{s}} = 5.230\; {\rm N}.

The spring in this question was stretched downward from its equilibrium by:

\begin{aligned} x &= (70\; {\rm cm} - 110\; {\rm cm}) \\ &= (-40)\; {\rm cm} \\ &= (-0.40) \; {\rm m}\end{aligned}.

(Note that x is negative since this displacement points downwards.)

Rearrange Hooke's Law to find k in terms of F_{\text{s}} and x:

\begin{aligned} k &= \frac{F_{\text{s}}}{-x} \\ &\approx \frac{5.230\; {\rm N}}{-(-0.40)\; {\rm m}} \\ &\approx 13\; {\rm N \cdot m^{-1}}\end{aligned}.

3 0
2 years ago
Using Planck’s constant as h = 6.63 E-34 J*s, what is the wavelength of a proton with a speed of 5.00 E6 m/s? The mass of a prot
Marrrta [24]
De Broglie's identity gives the relationship between the momentum and the wavelength of a particle:
p=mv= \frac{h}{\lambda}
where
p is the particle momentum
m is its mass
v its velocity
h is the Planck constant
\lambda is the wavelength

By re-arranging the equation, we get
\lambda=  \frac{h}{mv}
and by using the data about the proton, given in the text, we can find the proton's wavelength:
\lambda= \frac{h}{mv} = \frac{6.63 \cdot 10^{-34} Js}{(1.66 \cdot 10^{-27} kg)(5.00 \cdot 10^6 m/s)} =7.99 \cdot 10^{-14} m
6 0
3 years ago
Define Newton's third law:
Kisachek [45]

Answer:

the answer is B

Explanation:

the law states that for every action there is an equal and opposite reaction. action and reaction forces always act on two two different bodies and therefore THEY ALWAYS EXIST IN PAIRS.

3 0
3 years ago
An accelerating voltage of 2.47 x 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horiz
Dmitry [639]

Answer:

6.3445×10⁻¹⁶ m

Explanation:

E = Accelerating voltage = 2.47×10³ V

m = Mass of electron

Distance electron travels = 33.5 cm = 0.335 cm

E=\frac{mv^2}{2}\\\Rightarrow v=\sqrt{\frac{2E}{m}}\\\Rightarrow v=\sqrt{\frac{2\times 2470\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=29455356.08671\ m/s

Deflection by Earth's Gravity

\Delta =\frac {gt^2}{2}

Now, Time = Distance/Velocity

\Delta =\frac {g\frac{s^2}{v^2}}{2}\\\Rightarrow \Delta =\frac{9.81\frac{0.335^2}{29455356.08671^2}}{2}\\\Rightarrow \Delta =6.3445\times 10^{-16}\ m

∴ Magnitude of the deflection on the screen caused by the Earth's gravitational field is 6.3445×10⁻¹⁶ m

3 0
3 years ago
Help, anyone?? please:/
NeTakaya
A,E,C,B,D is the order
5 0
3 years ago
Other questions:
  • What is the kinetic energy of a toy truck with a mass of 0.75 kg and a velocity of 4 m/s? (Formula: )
    10·2 answers
  • If the speed of light in air is 3.00 times 10 to the 8 m/s power and the speed of light in water is 2.25 times 10 to the 8 power
    13·1 answer
  • Two vectors of magnitudes 30 units and 70 units are added to each other. What are possible results of this addition? (section 3.
    11·1 answer
  • Two coaxial cylindrical conductors are shown in perspective and cross-section above. The inner cylinder has radius a = 2 cm, len
    6·1 answer
  • Which observation can BEST be explained by the scattering of light? A) A pencil appears bent when placed in water. B) An oil dro
    12·2 answers
  • What type of circuit is shown?
    9·2 answers
  • More facts about mental health
    15·1 answer
  • HELP PLEASE...Arnold built a machine to help deliver the morning paper.He had to pull with 38N of force to move a stack of paper
    7·1 answer
  • Pls help me to answer this​
    13·1 answer
  • Which best explains horatio’s error? magnetism is not produced by electric currents unless the wire is coiled. the magnetic fiel
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!