If both nuggets have the same mass and different densities then it can be concluded that the volume with the highest density is smaller.
For, so to speak, density is a relation of how much mass is there in a given volume. So the more the mass and the smaller the volume, the greater the density.
To verify this, let us calculate the volumes of iron pyrite and gold pyrite.
For the iron pyrite nugget:
density = mass / volume
volume = mass / density
volume = 50/5
volume = 10cm3
For the gold nugget:
volume = mass / density
volume = 50 / 19.3
volume = 2.59cm3
Therefore it is found that the nugget with the highest density (gold) is the one with the lowest volume.
The two satellites orbit around the same planet, so we can use Kepler's third law, which states that the ratio between the cube of the radius of the orbit and the orbital period is constant for the two satellites:
where
is the orbital radius of the first satellite
is the orbital radius of the second satellite
is the orbital period of the first satellite
is the orbital period of the second satellite
If we use the data of the problem and we re-arrange the equation, we can calculate the orbital period of the second satellite:
(6) Wagon B is at rest so it has no momentum at the start. If <em>v</em> is the velocity of the wagons locked together, then
(140 kg) (15 m/s) = (140 kg + 200 kg) <em>v</em>
==> <em>v</em> ≈ 6.2 m/s
(7) False. If you double the time it takes to perform the same amount of work, then you <u>halve</u> the power output:
<em>E</em> <em>/</em> (2<em>t </em>) = 1/2 × <em>E/t</em> = 1/2 <em>P</em>
<em />
Speed=0.3*100=30m/s
speed=0.1*50=5m/s
frequency=20/0,5=40HZ
frequency=80/0.2=400HZ
frequency=120/0.4=300HZ
wavelength=340/440=0.77m
wavelength=340/880=0.39m
wavelength=250/400=0.63m
speed=2*50=100m/s
speed=0.5*100=50m/s
