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svet-max [94.6K]

4 years ago

7

What is the average horizontal component of force exerted on his feet by the ground during acceleration?

1 answer:

Arte-miy333 [17]4 years ago

7 0

Well you have to think of it like electricity go through your answer closes to that and figure it out

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1 m is equivalent to how many centimeters in the metric system

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How do uplift and erosion help to form a batholith?

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Please Help! Which of the following will not contribute to resource conservation?

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4 years ago

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you drop a 2 kg book to a friend who stand on the ground at distance D=10.0 m below, if your friends out streched hand at distan

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4 years ago

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if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?

Scrat [10]

Answer:

It requires <u>1.9 seconds</u> to reach maximum height.

Explanation:

As per given question,

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

$\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}$

Maximum height = S

Time taken is "t"

<u>Calculating time taken to reach maximum height:</u>

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

$0=19+10 \times t$

$-19=10 \times t$

$\frac{-19}{10}=t$

t = 1.9 seconds.

The time taken to reach maximum height is <u>1.9</u> seconds.

<u>Calculating maximum height</u>:

$\text { Consider the equation } V^{2}-U^{2}=2 a S$

Solving the equation we will get the value of S

$0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }$

-361 = -20S

Negative sign cancel both the sides.

$\mathrm{S}=\frac{361}{20}$

S = 18.05 m

Maximum height is 18.05 m .

3 0

3 years ago