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kicyunya [14]
3 years ago
10

As you approach your vehicle and perform checks it is not necessary to always

Physics
1 answer:
Greeley [361]3 years ago
4 0
1.) Have your keys in hand before approaching or entering your car.

2. Be alert to other pedestrians and drivers.

3.) Search for signs of movement between, beneath and around objects to both sides of your vehicle

4.) check the spare tire for proper inflation
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in a railyard a train is being put together from freight cars.An empty freight car coasting 10 m/s strikes a loaded car that is
svetoff [14.1K]

Answer:m1v1 + m2v2 = (m1f + m2f)vf. 3000kg(10.0m/s) + (15000kg)(0.0m/s) = (18000kg)(vf).

Explanation:

7 0
2 years ago
According to the Periodic Table of Elements, Calcium (Ca) has:
RSB [31]

Answer:

A- 20 protons and 20 electrons

Explanation:

8 0
3 years ago
How far can a mother push a 20.0 kg baby carriage, using a force of 62 N, if she can only do 2920 J of work? (Round to include t
alexgriva [62]
The mathematical definition of work (W) is force (F) multiplied by distance (x). In order to determine the distance for fixed force and work the above equation needs to be rearranged to make x the subject. The work divided by the force is equal to the distance. In this case the mother can push the baby carriage by a distance equal to 2920 divided by 62, which is 47.1 metres. 
5 0
3 years ago
Ferns spread spores instead of seeds, and some ferns eject the spores at surprisingly high speeds. One species accelerates 1.4 μ
marta [7]

Answer:

Impulse is 6.3*10^{-9}\:N \cdot s

The average force is 6.3*10^{-6} N

Explanation:

When a mass m undergoes a change in velocity \Delta v, its impulse I is

I =m\Delta v

and if a force F is acting for time t, then the impulse I is given by

I=F*t

Now the mass of the spores in kg is

m=1.4*10^{-6}g*\frac{10^{-3}kg}{g}=1.4*10^{-9}kg

we calculate the impulse from the first formula:

I =m\Delta v =(1.4*10^{-9}kg)(4.5\frac{m}{s} )=6.3*10^{-9}N\cdot s

\boxed{I=6.3*10^{-9}\:N \cdot s}

Now that we have impulse, we calculate the average force on the spore from the second formula:

F=\frac{I}{t} =\frac{6.3*10^{-9}}{1*10^{-3}s}=6.3*10^{-6} N

\boxed{F=6.3*10^{-6} N}

5 0
3 years ago
A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock
gtnhenbr [62]
F = m  \frac{v^2}{r}

F= 0.58  \frac{4.5^2}{0.5}  = 23.49 N

5 0
3 years ago
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