All categories

2 years ago

And I need help with seven and eight only I will appreciate it

Physics

1 answer:

Mumz [18]2 years ago

8 0

Answer:

7] Force = mass × acceleration

Force = 2 × 5

Force = 10 N

8] Velocity = acceleration due to gravity × time taken

Velocity = 9.8 × 12

Velocity = 117.6 m/s

You might be interested in

mike shoots a large marble (Marble A, mass:0.05 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble

mixas84 [53]

Explanation:

According to Conservation of Linear Momentum :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$0.05 \times 0.6 + 0.03 \times 0 = 0.05 \times - 0.2 + 0.03 \times v_2$

$0.04 = 0.03v_2$

Velocity of marble B after collision = 1.33 m/sec

7 0

3 years ago

Find the angle of incidence at which a light beam traveling from a medium having the index of refraction n1 = 2.7 to another med

luda_lava [24]

Answer:

The angle of incidence at which total internal reflection takes place will be equal to $\Theta _c=36.34^{\circ}$

Explanation:

We have given that light is traveling from a medium of refractive index x 2.7 to a medium of refractive index 1.6

So refractive index of first medium $n_1=2.7$ and $n_2=1.6$

We have to find the angle of incidence for total internal reflection

For total internal reflection

$n_1sin\Theta _c=n_2sin90^{\circ}$

$\Theta _c=sin^{-1}\frac{n_2}{n_1}$

$\Theta _c=sin^{-1}\frac{1.6}{2.7}$

$\Theta _c=36.34^{\circ}$

So the angle of incidence at which total internal reflection takes place will be equal to $\Theta _c=36.34^{\circ}$

7 0

3 years ago

A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the

Lelu [443]

Answer:

Average power output of insect is 2.42W

Explanation:

Workdone by constant force during displacement is given by:

W= F× d cos theta

Where theta is angle between F and d.

Power output due to the force over the interval time is given by:

P= Workdone/change in time

Ginen:

Mass of insect,m= 7.0g= 7/1000 = 0.07kg

Downward force applied by insect,F= 2mg

Distance moved by the wing each stroke=1.5cm=1.5/100= 0.015m

W= F× d cos theta

Where theta=0° since force is in the same direction as the displacement.

W= 2mg×d

W= 2× 0.07 × 9.8 × 0.015

W= 0.02058J

Power output = W/ change in time

Since wings make 117strokes each second time interval is 1/117 = 8.5×10^-3seconds

Power= 0.02058/(8.5×10^-3)

Power= 2.42W

6 0

3 years ago

Two football players with mass 75 kg and 100 kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively. if t

3241004551 [841]

heyaaaaa

Momentum before Pb = momentum after Pa

Pb = 75*6 - 100*8 = -350kgm/s = Pa = (75+100)V where V is the velocity of the combined mass of the two players after the collision.

Velocity has magnitude (speed) and direction. V = -350/175 = -2m/s

So the two players are moving at 2m/s in the direction the 100kg player was moving before the collision.

I arbitrarily chose the direction of the smaller player as positive so the opposite direction (of the larger player) had to be negative.

hope it helpssss!!!!!!

6 0

3 years ago

A stone was dropped off a cliff and hit the ground with a speed of 88 ft/s . What is the height of the cliff? (Use 32 ft/s 2 for

bulgar [2K]

To solve this problem we will apply the linear motion kinematic equations, which describe the change in velocity, depending on the acceleration and the distance traveled, that is,

$v_f^2 = v_i^2 +2ah$

Where,

$v_f$ = Final Velocity

$v_i$ = Initial Velocity

a = Acceleration

h = height

Our values are given as,

$v_f = 88 ft/s\\v_i = 0 ft /s\\a = 32 ft/s^2\\$

Replacing we have,

$vf^2 = vi^2 + 2*a*h$

$88^2 = 0 + 2*32*h$

$h= 121 ft$

Therefore the height of the cliff is 121ft

5 0

3 years ago