The force of friction is zero.
Using F = m a = the force needed is 6 N which means no friction can be acting.
<span>This problem is solved by the equation of motion:
x = x0 + v0*t + 1/2*a*t^2,
Here x0 = 0, v0 = 40ft/sec and a = -5 ft/s^2, we need to solve for t:
v = v0 + a*t, solve how long does it take to stop: 0 = v0 + a*t --> a*t = -v0 --> t = -v0/a
-- > 40/5 = 8 seconds to stop.
In this time, the car travels x = 0 + 40*8 + 0.5*-5*8^2 ft ~ 160 ft.
Answer: The car travels 160 ft.</span>
<em><u>Five</u></em>
This is exactly like your question 2. You need only substitute the given numbers here.
Givens
- N = 100 turns
- delta B = 0.25
- r = 0.04
- Area = pi * r^2 = 3.14 * 0.04^2 = 5.02 * 10^-3
- Cos 60 = 1/2 = 0.5
Formula
e = N * delta B * Area * cos phi
Solution
e = - 100 * 0.25 * 5.02 * 10^-3 * 0.5
e = 0.0628 = 0.063
Answer
A
<em><u>Six</u></em>
This is a notes question. The result is a sine curve. I don't know how they are counting the change in direction. Is a rising curve different from a falling curve? For sure going from plus to minus is a change in direction, but I still don't know how to count it. It will depend on what you have been told.
I would answer 4 but this is by no means certain. The only other possible answer is 2
Answer: mathematical model
Explanation: just took the test
Answer:
v = 1.7 m/s
Explanation:
Given that,
Initial velocity of the object, u = 1 m/s
Acceleration of the object, a = 1 m/s²
We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.
So, the final velocity of the object is 1.7 m/s.
