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ICE Princess25 [194]
3 years ago
13

Can someone please help me with this question? Thank you!

Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer: A

<u>Step-by-step explanation:</u>

\stackrel\frown{XY} ≅ \stackrel\frown{YZ}

⇒ ∠XOY ≅ ∠ZOY

\overline{XO} ≅ \overline{ZO} since they are both a radius

\overline{OY} ≅ \overline{OY} based on reflexive property

∴ ΔXOY ≅ ΔZOY by SAS

So, \overline{XY} ≅ \overline{ZY} by CPCTC

ZY = 10.2 is given

so, XY = 10.2 by substitution property


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Can someone help me with this please
stellarik [79]

Ok so we'll  go ahead and solve for y first -  we just need to get it alone on one side of the equal sign

Step 1: subtract 2x from each side

2x - 7y - 2x = 19 - 2x

This cancels out the 2x on the left, giving us

-7y = 19 - 2x

Step 2: divide both sides by -7

\frac{-7y}{-7} = \frac{19}{-7} + \frac{-2x}{-7}

This gives us

y = -19/7 + 2x/7

That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.

When x = -3

y = -19/7 + 2x/7

y = -19/7 + 2(-3)/7

y = -19/7 - 6/7

y = -25/7


When x = 0

y = -19/7 + 2x/7

y = -19/7 + 2(0)/7

y = -19/7


When x = 3

y = -19/7 + 2x/7

y = -19/7 + 2(3)/7

y = -19/7 + 6/7

y = -13/7


Hope that helps! Feel free to ask if I can help with anything else :)

7 0
3 years ago
Determine whether the set, together with the indicated operations, is a vector space. if it is not, then identify at least one o
lesya692 [45]
<span>Where is The set?? can you add it please</span>
3 0
3 years ago
15b^2+20y^3<br> Find the greatest common factor
Andrew [12]

Answer:

Hope this helps!

Step-by-step explanation:

The GCF is 5

8 0
3 years ago
The quotient of 24 and x equals 14 minus 2 times x (into an equation don’t solve)
Katen [24]

Answer:

24 / x = 14 - 2x

Step-by-step explanation:

Quotient means division (÷ or /)

Quotient of 24 and x = 24 ÷ x

24 ÷ x is equivalent to 24 / x

14 minus 2 times x = 14 - 2x

So, the equation is

24 / x = 14 - 2x

7 0
3 years ago
Which expression is equivalent to square root 55x^7y6/11x^11y^8
Novay_Z [31]

Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

6 0
3 years ago
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