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Ad libitum [116K]
4 years ago
5

Consider a galvanic cell in which Al 3 + Al3+ is reduced to elemental aluminum and magnesium metal is oxidized to Mg 2 + Mg2+ .

Write the balanced half-cell reactions that take place at the cathode and at the anode.

Chemistry
2 answers:
valina [46]4 years ago
8 0

Explanation:

Below is an attachment containing the solution.

olga nikolaevna [1]4 years ago
5 0

Answer:

Anode:

3Mg(s) ----------> 3Mg2+(aq) + 6e

Cathode:

2Al3+(aq) +6e ---------> 2Al(s)

Explanation:

Anode:

3Mg(s) ----------> 3Mg2+(aq) + 6e

Cathode:

2Al3+(aq) +6e ---------> 2Al(s)

Magnesium is more electro positive than aluminum hence it functions as the anode. Six electrons are lost/gained in the redox process as shown in the oxidation and reduction half reaction equations above. Magnesium is oxidized to magnesium ion while aluminum is reduced to elemental aluminum.

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Answer:

96g

Explanation:

Given parameters:

Number of moles of NaOH = 2.4moles

Unknown:

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Solution:

The mass of a substance given the number of moles can be found using the expression below;

     Mass of NaOH  = Number of moles x molar mass;

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Now input the parameters and solve;

    Mass of NaOH  = 2.4 x 40  = 96g

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Explanation:

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