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Galina-37 [17]
3 years ago
15

What is a very strong dipole-dipole force?​

Chemistry
1 answer:
nadezda [96]3 years ago
8 0

Answer: Dipole-dipole forces: electrostatic interactions of permanent dipoles in molecules; includes hydrogen bonding.

Explanation:

https://courses.lumenlearning.com/introchem/chapter/dipole-dipole-force/- More on the Topic not sure if this will help though?

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Give the ΔH value for the decomposition of silver chloride as shown in the reaction 2AgCl(s)+127 kJ→2Ag(s)+Cl2(g).
choli [55]

Answer: \Delta H=+127kJ

Explanation:

2AgCl(s)+127kJ\rightarrow 2Ag(s)+Cl_2(g)  

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and \Delta H for the reaction comes out to be positive.

As the heat is absorbed the reactants , the reaction is endothermic and \Delta H for the given endothermic reaction will be +127 KJ

6 0
4 years ago
Which discovery is most directly related to careers in biology?
Nookie1986 [14]
Molecular and Microbiology 
5 0
4 years ago
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
3 years ago
Muiltplying 2.5 x 10^10 by 3.5 x 10^-7
andrey2020 [161]

<u>Answer: </u>

The value of \left(2.5 \times 10^{10}\right) \times\left(3.5 \times 10^{-7}\right) is 8750

<u>Solution: </u>

\left(2.5 \times 10^{10}\right) \times\left(3.5 \times 10^{-7}\right)

\Rightarrow\left(2.5 \times 10^{10} \times 3.5 \times 10^{-7}\right)

\Rightarrow\left(2.5 \times 3.5 \times\left(10^{10} \times 10^{-7}\right)\right)

\Rightarrow(2.5 \times 3.5) \times\left(10^{10+(-7)}\right)

\Rightarrow(2.5 \times 3.5) \times\left(10^{10+(-7)}\right)

\Rightarrow(2.5 \times 3.5) \times 10^{3}

\Rightarrow 8.75 \times 10^{3}

\Rightarrow 8.75 \times 1000=8750

6 0
3 years ago
Flammability is a material’s ability to burn in the presence of
frosja888 [35]

Answer:

Flammability is a material’s ability to burn in the presence of <u><em>oxygen.</em></u>

Explanation:

Flammability can be described as the ability of a substance to get ignited. Flammability will lead to fire or combustion. Some substances are highly flammable like Benzene. Other tend to be just flammable. And there are also compounds which will nor be flammable at all as they won't react with oxygen. Examples of these substances include helium, steel or glass.

The flammability of a substance shall be considered a very important aspect when storing or transporting a substance.

5 0
3 years ago
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