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Ugo [173]
3 years ago
12

(1- name 1 of Faouzia’s songs from her stripped album

Physics
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer:

I thought  "Born Without a Heart" was pretty good.

Hi

Explanation:

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A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,=1.91 m and 1,=−2.73 m in
Elena-2011 [213]

Answer:

Components: 0.0057, -0.0068. Magnitude: 0.0089 m/s

Explanation:

The displacement in the x-direction is:

d_x = 3.65-1.91=1.74 m

While the displacement in the y-direction is:

d_y = -4.79 -(-2.73)=-2.06 m

The time taken is t = 304 s.

So the components of the average velocity are:

v_x = \frac{d_x}{t}=\frac{1.74}{304}=0.0057 m/s

v_y = \frac{d_y}{t}=\frac{-2.06}{304}=-0.0068 m/s

And the magnitude of the average velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{(0.0057)^2+(-0.0068)^2}=0.0089 m/s

8 0
3 years ago
a) A space vehicle is launched vertically upward from the Earth's surface with an initial speed of 8.90 km/s, which is less than
elena-14-01-66 [18.8K]

Answer:

A) 4037.2[km]; B) 21472[m/s]

Explanation:

A)

This part can be solved using the principle of energy conservation, where kinetic energy will be equal to potential energy. We will define the kinetic energy and the potential energy.

Ek= 0.5*m*v^2\\where:\\m = mass [kg]\\v = 8.90*10^3[m/s]\\Ep=m*g*h\\where:\\g = gravity = 9.81[m/s^2]\\h = elevation or height [m]\\

Now we have to match both equations in this way the mass value is canceled and we can clear h.

0.5*m*(8.9*10^3)^{2}=m*9.81*h\\ h=4037206.93[m] = 4037.2[km]

B)

To solve this problem we can use the kinematic equations, but first we must identify the initial data:

yo = 2.35*10^7[m]

y = 0 [m] when hit the ground [m]

vo = 0 [m/s], It is essentially at rest...

v_{f} ^{2} =v_{o} ^{2} +2*a*(y)\\v_{f} =\sqrt{2*9.81*2.35*10^{7} } \\v_{f} =21472.54[m/s] o 21.47[km/s]

4 0
3 years ago
Suppose the car now accelerates from 0 m/s to 30.0 m/s in 5.00 s. If the wheels have a radius of 24.1 cm, what is their angular
Anettt [7]

The answer is 25 and 50.3

6 0
3 years ago
If Becky expects to lose 20 pounds in 2 weeks, she has _____.
denpristay [2]
She needs to lose an average of 10 pounds per week in order to fulfill her expectation. Go Becky !
8 0
3 years ago
Read 2 more answers
A signal is sampled at 10000 Hz and a total of 1024 data samples are taken, what are the highest and lowest frequencies that can
tia_tia [17]

Since the discrete Fourier series, the Sampling rate, would be the equivalent of the inverse of the passage of time, that is, to the frequency, mathematically this can be written as,

\frac{1}{\Delta t} = 10000Hz

In turn, the time can be described depending on the period and the amount of data samples taken. This would be,

\Delta t = \frac{T}{m}

Here,

m = Data Samples

T = Period

Replacing,

\Delta t = \frac{T}{1024}

Replacing the value of the time from the first equation,

\frac{1024}{T} = 10000

T = 102.4ms

At the same time, the range then will be given between the basic frequency to the half of the sample, that is,

f_{min} = \frac{1}{T} = 9.165Hz

f_{max} = \frac{1024}{2} (9.165Hz)

f_{max} = 5000Hz

Therefore the lowest frequency is 5000Hz and highest 9.165Hz

7 0
3 years ago
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