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Naily [24]
3 years ago
5

Which of the following factors used in a dimensional analysis calculation have a finite number of significant figures (in other

words, they are not exact numbers) that might limit the precision of the calculated value?
A. A conversion factor for time of (60 min/1 hour)
B. A conversion factor for distance of (1000 m/1 km)
C. A measurement of speed equaling (27.7 km/hour)
D. None of the above
Chemistry
1 answer:
lys-0071 [83]3 years ago
8 0

Answer: Option C

A measurement of speed equaling (27.7 km/hour)

Explanation:

It is measurement of speed equaling (27.7 km/hour) because it is a factor used in dimensional analysis because it is a problem solving method that involve the use of number or expression which can be multiplied without affecting or causing a change in the value of the expression.

27.7km/he is not the exact number that can limit the precision of the calculated value or accurate value.

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What is Supersaturation? (I think its D. But i dont know)
trapecia [35]

Explanation:

Supersaturation occurs with a chemical solution when the concentration of a solute exceeds the concentration specified by the value equilibrium solubility. Most commonly the term is applied to a solution of a solid in a liquid.

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3 years ago
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Explain the process of fermentation.
tia_tia [17]

Answer:

Fermentation, chemical process by which molecules such as glucose are broken down anaerobically. More broadly, fermentation is the foaming that occurs during the manufacture of wine and beer, a process at least 10,000 years old. The frothing results from the evolution of carbon dioxide gas, though this was not recognized until the 17th century.

Explanation:

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Calculate the molality, molarity, and mole fraction of FeCl3 in a 29.5 mass % aqueous solution (d = 1.283 g/mL).
faltersainse [42]

Answer:

molality FeCl3= 2.579 molal

molarity FeCl3 = 2.333 M

mol fraction FeCl3 = 0.0444

Explanation:

Step 1: Data given

Mass % = 29.5 %

Density = 1.283 g/mL

Molar mass FeCl3 = 162.2 g/mol

Step 2: Calculate mass solution

Suppose we have 1L = 1000 mL solution

Mass solution = 1.283 g/mL * 1000 mL = 1283 grams

Step 3: Calculate mass FeCl3

Mass FeCl3 = 0.295 * 1283 grams

Mass FeCl3 =  378.485 grams

Step 4: Calculate mass of water

Mass water = 1283 - 378.485 = 904.515 grams

Step 5: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 378.485 grams / 162.2 g/mol

Moles FeCl3 = 2.333 moles

Step 6: Calculate moles H2O

Moles H2O = 904.515 grams / 18.02 g/mol

Moles H2O = 50.195 moles

Step 7: Mol fraction FeCl3

Mol fraction FeCl3 = 2.333 / (50.195+2.333)

Mol fraction FeCl3 =   0.0444

Step 8: Calculate molality

Molality = moles FeCl3 / mass H2O

Molality = 2.333 moles / 0.904515 kg

Molality = 2.579 molal

Step 9: Calculate molarity

Molarity = moles / volume

Molarity FeCl3 = 2.333 moles / 1 L

Molarity FeCl3 = 2.333 M

8 0
3 years ago
Gas has a volume of 247.3 ML and is at 100 Celsius and 745 Hg. If the mass of the gas is 0.347 g what is the molar mass of the v
Ahat [919]

Answer:

The molar mass of the vapor is 43.83 g/mol

Explanation:

Given volume of gas = V = 247.3 mL = 0.2473 L

Temperature = T = 100^{\circ}C = 373 K

Pressure of the gas = P = 745 mmHg  (1 atm = 760 mmHg)

P = \displaystyle \frac{745}{760} \textrm{ atm} = 0.9802 \textrm{ atm}

Mass of vapor = 0.347 g

Assuming molar mass of gas to be M g/mol

The ideal gas equation is shown below

\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{ RT } \\0.98026 \textrm{ atm}\times 0.2473 \textrm{ L} = \displaystyle \frac{3.47 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 373\textrm{K} \\M = 43.834 \textrm{ g/mol}

The molar mass of the vapor comes out to be 43.834 g/mol

4 0
3 years ago
what happens to the yield of hydrogen if the reaction is carried out at a higher temperature but at the same pressure​
valkas [14]

Answer: It increases the rate of desulfurization at a constant feed rate

Explanation:

5 0
3 years ago
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