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Dmitry_Shevchenko [17]
3 years ago
8

Daniel tosses a number cube 19 fewer times than Jayden. Daniel tosses a number cube 38 times. How many times does Jayden toss a

number cube?
Mathematics
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer: Jayden toss a number cube 49 times.

Step-by-step explanation:

Hi, to answer this question we have to write an equation:

Daniel's number of tosses (D) will be equal to Jayden's number of tosses (J) minus 19 (since Daniel tosses a number cube 19 fewer times than Jayden)

D = J -19

Since Daniel tosses a number cube 38 times, D= 38

38 = J -19

Solving for J

30+19 =J

J = 30+19

J =49 times

Jayden toss a number cube 49 times.

Firlakuza [10]3 years ago
4 0
To find out how many times Jayden fosses, you need to add 19 to 38.
ANSWER: 57 times
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Step-by-step explanation:

To quickly determine the number of solutions of a linear system of equations, we need to express each of the equations in slope-intercept form, so we can compare their slopes, and decide:

1) if they intersect at a unique point (when the slopes are different) thus giving a one solution, or

2) if the slopes have the exact  same value giving parallel lines (with no intersections, and the y-intercept is different so there is no solution), or

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