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3 years ago

To what volume should 11.9 mL of an 8.00 M acetic acid solution be diluted to obtain a final solution that is 1.50 M?

Chemistry

1 answer:

artcher [175]3 years ago

6 0

Use M1V1 = M2V2
11.9(8) = 1.5V2
95.2 = 1.5(V2)
V2 = 63.5 mL

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<u>Explanation:</u>

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Moles of hydrogen gas = $3.91\times 10^{-2}mol$

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Putting values in above equation, we get:

$\text{Molarity of }H_2=\frac{3.91\times 10^{-2}mol}{0.250L}=0.1564M$

Average rate of the reaction is defined as the ratio of concentration of hydrogen generated to the time taken.

To calculate the average rate of the reaction, we use the equation:

$\text{Average rate of the reaction}=\frac{\text{Concentration of hydrogen generated}}{\text{Time taken}}$

We are given:

Concentration of hydrogen generated = 0.1564 M

Time taken = 20.0 minutes

Putting values in above equation, we get:

$\text{Average rate of the reaction}=\frac{0.1564M}{20.0min}\\\\\text{Average rate of the reaction}=7.82\times 10^{-3}M/min$

Hence, the average rate of the reaction is $7.82\times 10^{-3}M/min$

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2 years ago

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