3 years ago

To what volume should 11.9 mL of an 8.00 M acetic acid solution be diluted to obtain a final solution that is 1.50 M?

1 answer:

6 0

Use M1V1 = M2V2
11.9(8) = 1.5V2
95.2 = 1.5(V2)
V2 = 63.5 mL

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Percentage by mass of carbon = $\frac{(1*12.01\frac{g}{mol}) }{44.01\frac{g}{mol} } *100=27.3%$

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