Solve for Keq , given the following concentrations at equilibrium. Based on the calculated Keq, are products or reactants larger
1 answer:
You might be interested in
Answer : The molecular weight of this compound is 891.10 g/mol
Explanation : Given,
Mass of compound = 12.70 g
Mass of ethanol = 216.5 g
Formula used :
where,
= change in freezing point
= temperature of pure ethanol =
= temperature of solution =
= freezing point constant of ethanol =
i = van't hoff factor = 1 (for non-electrolyte)
m = molality
Now put all the given values in this formula, we get
Therefore, the molecular weight of this compound is 891.10 g/mol