Ask question

Ask question

All categories

3 years ago

13

Solve for Keq , given the following concentrations at equilibrium. Based on the calculated Keq, are products or reactants larger

?
CO2 = 3.0 M O2 = 1.5 M CO = 2.0 M

1 answer:

miv72 [106K]3 years ago

4 0

Answer:

it blows up very lighty

Explanation:

You might be interested in

A cylinder is filled with 10.0 L of gas and a piston is put into it. The initial pressure of the gas is measured to be 273. kPa.

Ann [662]

P2 = 54.6 kPa

Explanation:

Given:

V1 = 10.0 L. V2 = 50.0 L

P1 = 273 kPa. P2 = ?

We can use Boyle's law to solve this problem.

P1V1 = P2V2

Solving for P2,

P2 = (V1/V2)P1

= (10.0 L/50.0 L)(273 kPa)

= 54.6 kPa

5 0

3 years ago

Provide the IUPAC name for the following compound: a. 2,4,5-Trimethyl-4-propylheptane b. 4-Isobutyl-4,5-dimethylheptane c. 4-sec

mel-nik [20]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is A

That is 2,4,5-Trimethyl-4-propylheptane

Explanation:

Looking at the structure the longest carbon chain is 7 as shown on the second uploaded image

Also from the diagram of the structure we can identify that is longest chain has 3 methyl group attachment and one propyl group attachment

Now going through this longest chain the numbering of this attachment them the lowest number is the correct way so as we can see

2,4,5-Trimethyl-4-propylheptane gives the lowest numbering compared to 3,4,6-Trimethyl-4-propylheptane so the correct IUPAC names is 2,4,5-Trimethyl-4-propylheptane

8 0

4 years ago

All atoms of the same element have the same what??

yKpoI14uk [10]

All atoms of the same element have the same atomic number

8 0

3 years ago

How many codons are needed to specify 3 amino acids?

Nataliya [291]

There need be 9 amino acids, as each amino acid is composed of 3 codons.
Hope this helps!

5 0

3 years ago

The equation for another reaction used in industry isCO(g) + H₂O(g) <img src="https://tex.z-dn.net/?f=%5Crightleftharpoons" id="

Sloan [31]

Answer:

(i) CO = 0.4 mol; H₂O = 1.6 mol; Kc = 4

(ii) CO = 0.67 mol; H₂O = 0.67 mol; CO₂ = 1.33 mol; H₂ = 1.33 mol

Explanation:

(i) For the equation given let's make a table of the concentrations for equilibrium (the volume is constant, so, we can do it with moles number)

CO(g) + H₂O(g) ⇄ H₂(g) + CO₂(g)

2.0 mol 3.2 mol 0 0 <em>Initial</em>

-x -x +x +x <em>Reacts</em> (stoichiometry is 1: 1: 1: 1)

2.0-x 3.2-x x x <em>Equilibrium</em>

In the equilibrum, the moles number of hydrogen and carbon dioxide are 1.6 mol, so x = 1.6 mol

The amounts of CO and H₂O are:

CO = 2.0 - 1.6 = 0.4 mol

H₂O = 3.2 - 1.6 = 1.6 mol

The constant of the equilibrium is the multiplications of the concentrations of products divided by the multiplication of the concentration of the reactants (all the concentrations elevated to the coefficient). So:

Kc = (1.6x1.6)/(0.4x1.6)

Kc = 1.6/0.4

Kc = 4

(ii) Kc must remais constant (it only changes with the temperature), so let's construct a new table of equilibrium:

CO(g) + H₂O(g) ⇄ H₂(g) + CO₂(g)

2.0 mol 2.0 mol 0 0 <em>Initial</em>

-x -x +x +x <em>Reacts</em> (stoichiometry is 1: 1: 1: 1)

2.0-x 2.0-x x x <em>Equilibrium</em>

Kc = (x*x)/((2.0-x)*(2.0-x))

4 = x²/(4 - 4x + x²)

16 - 16x + 4x² = x²

3x² - 16x + 16 = 0

Using Baskhara's equation:

Δ =(-16)² - 4x3x16

Δ = 256 - 192

Δ = 64

x = (-(-16) +/- √64)/(2*3)

x' = (16 + 8)/6 = 4

x'' = (16 - 8)/6 = 1.33

x must be small than 2.0, so x = 1.33 mol, which is the amount of hydrogen and carbon dioxide at equilibrium. The both reactants has 2.0 - 1.33 = 0.67 mol at equilibrium.

5 0

3 years ago