Answer: We will use the electron-dot structure to tell the reactivity of fluorine.
Explanation: Fluorine atom is the 9th element of the periodic table.
Atomic number: 9
Electronic configuration of fluorine =
The number of valence electrons = 7
and the valency for this element = 1 (because this element requires only one electron to have a stable electronic configuration)
Electron dot structures are the structures which represent the valence electrons present around the nucleus of an atom. The dots in the structures represent the electrons.
Reactivity of an element is defined as its ability to gain or loose electrons easily.
As fluorine atom gains 1 electron easily, so it is very reactive.
Electron dot structure of fluorine atom is given in the image attached.
Answer:
The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.
Explanation:
Using Boyle's law
Given ,
V₁ = 3.6 L
V₂ = ?
P₁ = 1.0 atm
P₂ = 13.3 atm (From correct source)
Using above equation as:
The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.
Answer:
Explanation:
The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.
1 .Calculate the hydronium ion concentration
We can use an ICE table to organize the calculations.
HF + H₂O ⇌ H₃O⁺ + F⁻
I/mol·L⁻¹: 2.7 0 0
C/mol·L⁻¹: -x +x +x
E/mol·L⁻¹: 2.7 - x x x
2. Calculate the pH
3. Calculate [C₆H₅O⁻]
C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺
2.7 x 0.0441