Question

Plz help! 17 points!

Answer 1

Answer:

2.  C. { 0, 1, 2}

3.  B. 53

6.  P = 14n + 10

Step-by-step explanation:

2.  The domain is the input values (or the x values)

The domain is { 0,1,2}

3.  f(x) = 5x+3

 where x is the number of minutes.  We will let x = 10

f(10 ) = 5*10 +3

       = 50+3

      = 53

53 cars will pass

6.  When we have 1 trapezoid, the perimeter is 5+5+8+6 = 24

When we have 2 trapezoids, the perimeter is 5+8+6+5+8+6 = 38

We add 14, when we add a second trapezoid

P = 14n + 10

p(1) = 14+10   Check for 1 trapezoid

p(2) = 14*2 +10 = 28+10 = 38    check for 2 trapezoids

Answer 2

2. You're given a function that maps 1 to 1, 0 to 0, and 2 to -1. The domain is the set of points that are given to the function as inputs, {1, 0, 2}, which is equivalent to the set listed in option C.

3. Evaluate $f(x)$ at $x=10$:

$f(10)=5(10)+3=50+3=53$

so the answer is B.

6. Each trapezoid in the chain contributes a copy of 8 and 6 (a total of 14), so that we should expect the total perimeter to contain $14n$. The remaining two sides contribute a constant 10 regardless of $n$. So the perimeter is given by the formula in D, $P=14n+10$.