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yulyashka [42]
3 years ago
6

for much of the year this desert is hot dry and windy.What type of plant would you most expect to survive in this climate

Physics
1 answer:
abruzzese [7]3 years ago
7 0
I think the answer is cactus
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Laws of motion are important for the study of objects that are not in motion and objects in motion. Is it true or false?
e-lub [12.9K]
Gotta be true because physics
3 0
3 years ago
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Which statement describes how work and power are similar?
gizmo_the_mogwai [7]

Answer:

C: You must know force and distance to calculate both.

Explanation:

A force is said to have done work, when it has succeeded in causing displacement in an object from its starting point.

Power can be defined as the rate of doing work.

The work can be calculated using the following formula:

Work done = Force × Displacement

The power can be calculated using the following formula:

Power = Work \ Time

In order to calculate the work and power, the force and distance should be known. The force and distance will help in the calculating the work, which will in turn help in the calculation of the power of the object.

Hence, the answer is you must know force and distance to calculate both.

4 0
3 years ago
A drone is flying horizontally when it runs out of power and begins to free fall from 16 m. No drag. If it lands 40 m away (in t
marysya [2.9K]

Answer:

the horizontal velocity while it was falling is 22.1 m/s.

Explanation:

Given;

height of fall, h = 16 m

horizontal distance, x = 40 m

The time to travel 16 m is calculated as;

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 16}{9.8} } \\\\t = 1.81 \ s

The horizontal velocity is calculated as;

v_x = \frac{X}{t} \\\\v_x = \frac{40}{1.81} \\\\v_x = 22.1 \ m/s

Therefore, the horizontal velocity while it was falling is 22.1 m/s.

7 0
3 years ago
What is the kinetic energy of a 0.15 kg baseball that is moving with a velocity of 50 m/s?
goblinko [34]
Using the equation:

ke \:  =  \frac{1}{2} m{v}^{2}
ke  =   \frac{1}{2} (0.15) {(50)}^{2}
ke  = 188  \: (3sf)


Ans: 188 J
7 0
3 years ago
9) An object with a height of 18 cm is placed in front of a converging lens. The image has a
vovikov84 [41]

Answer:

Explanation:

a) Magnification = image height / object height = -9 / 18 = -0.5

b) Magnification = - image distance / object distance = -0.5

so image distance = 0.5 object distance

1/focal length = 1/image distance + 1/object distance

1/6 = 1/(0.5 object distance) + 1/object distance

object distance = 18.0 cm

c) Image appears behind the lens.

6 0
3 years ago
Read 2 more answers
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