2 clues about a chemical change

The water side of the wall of a 60-m-long dam is a quarter-circle with a radius of 7 m. Determine the hydrostatic force on the d

tamaranim1 [39]

Answer:

$26852726.19\ \text{N}$

$57.52^{\circ}$

Explanation:

r = Radius of circle = 7 m

w = Width of dam = 60 m

h = Height of the dam will be half the radius = $\dfrac{r}{2}$

A = Area = $rw$

V = Volume = $w\dfrac{\pi r^2}{4}$

Horizontal force is given by

$F_x=\rho ghA\\\Rightarrow F_x=1000\times 9.81\times \dfrac{7}{2}\times 7\times 60\\\Rightarrow F_x=14420700\ \text{N}$

Vertical force is given by

$F_y=\rho gV\\\Rightarrow F_y=1000\times 9.81\times 60\times \dfrac{\pi 7^2}{4}\\\Rightarrow F_y=22651982.59\ \text{N}$

Resultant force is

$F=\sqrt{F_x^2+F_y^2}\\\Rightarrow F=\sqrt{14420700^2+22651982.59^2}\\\Rightarrow F=26852726.19\ \text{N}$

The hydrostatic force on the dam is $26852726.19\ \text{N}$ .

The direction is given by

$\theta=\tan^{-1}\dfrac{F_y}{F_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{22651982.59}{14420700}\\\Rightarrow \theta=57.52^{\circ}$

The line of action is $57.52^{\circ}$ .

7 0

2 years ago

HEEEEELP!!!!!! :((( help me with this exercise.

kirill [66]

Answer:

See the graph attached with the vectors.

Explanation:

The exercise is to draw the corresponding vectors:

$2\vec a\\\\3\vec c\\\\3\vec d\\\\3\vec f\\\\2\vec b$

Every one is the multiplication of a scalar by a vector.

The result of multiplying a scalar by a vector is a vector with the same direction of the original vector enlarged in a factor equal to the scalar magntitude.

Thus, in a graph the resulting vector is represented with a parallel arrow and pointing in the same direction as the original vector but with a length equal to the original length multiplied by the magnitude of the scalar.

For instance, the vector $2\vec a$ is represented with an arrow in the same direction of $\vec a$ and with twice its length.

The figure attached contains the five requested vectors using the procedure explained above.

7 0

2 years ago

What is the value of n?

vekshin1

Answer:

THE ANSWE IS C

81

Explanation:

6 0

2 years ago

Read 2 more answers

In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push agains

Hoochie [10]

Answer:

$\frac{m_B}{m_E}=1.18$

Explanation:

$m_B$ = Mass of Bonzo

$m_E$ = Mass of Ender

$u_B$ = Initial Velocity of Bonzo = 2.2 m/s

$u_E$ = Initial Velocity of Ender = -2.6 m/s

From conservation of linear momentum

$m_Bu_B=m_Eu_E\\\Rightarrow \frac{m_B}{m_E}=\frac{u_E}{u_B}\\\Rightarrow \frac{m_B}{m_E}=\frac{2.6}{2.2}\\\Rightarrow \frac{m_B}{m_E}=1.18$

$\therefore \frac{m_B}{m_E}=1.18$

8 0

3 years ago

Given the equation p2 = a3, what is the orbital period, in days, for the planet venus? (venus is located 0.72 au from the sun?)

melisa1 [442]

The correct answer is 223 days.

The relationship between the duration of revolution and the separation between the sun is shown by Kepler's third law. Using the notions of circular motion and the gravitational and centripetal forces, we may obtain this equation.

According to Kepler's third rule, the semi-major axis of an orbit is linked to the orbital period of a planet around the sun as follows:

p² = a³

where an is the semi-major axis/distance to the star and p is the orbital period in years.

It is said that a = 0.72 AU for Venus.

P= √(0.72 AU)^3 = 0.61 years.

365 days in a year = 222.9 ≈ 223 days.

To learn more about Kepler's third rule refer the link:
brainly.com/question/1608361

#SPJ4

5 0

10 months ago