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TEA [102]
3 years ago
13

2 clues about a chemical change

Physics
1 answer:
Evgesh-ka [11]3 years ago
6 0
A change in color, a formation of gas or bubbles, temperature change. 
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Light of wavelength 500 nm is incident perpendicularly from air on a film 10-4cm thick and of refractive index 1.375. Part of th
Marysya12 [62]

Answer

given,

wavelength (λ)= 500 n m

thickness of film= 10⁻⁴ cm

refractive index = μ = 1.375

distance traveled is double which is equal to 2 x 10⁻⁴ cm

a) Number of wave

     N = \dfrac{d}{\mu\lambda}

     N = \dfrac{2 \times 10^{-6}}{1.375\times 500 \times 10^{-9}}

           N = 2.91

           N = 3

b) phase difference is equal to

Reflection from the first surface has a 180° (½λ) phase change.

There is no phase change for the 2nd surface reflection and there is no phase difference for the 2nd wave having traveled an exact whole number of waves.

net phase difference = 180^0\times \dfrac{3}{2}

                                   = 270°

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3 years ago
A car engine supplies 2.0 x 103 joules of energy during the 10. seconds it takes to accelerate the car along a horizontal surfac
andrew11 [14]

Answer: 2. 2.0*10^2 W

Explanation:

Power = Work/Time

Power = (2.0*10^3) Joules/10 seconds

Power = 2.0*10^2 Watts

7 0
2 years ago
Where can I find springs that are the same size as the ones in a mechanical pencil
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Staples, Bestbuy, Maybe Homedepot

Explanation:

5 0
2 years ago
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Suppose you run into a wall at 4.5 meters per second (about 10 mph). Let's say the wall brings you to a complete stop in 0.5 sec
STatiana [176]

Answer with Explanation:

We are given that

Initial velocity,u=4.5 m/s

Time=t =0.5 s

Final velocity=v=0m/s

We have to find the deceleration and estimate the force exerted by wall on you.

We know that

Acceleration=\frac{v-u}{t}

Using the formula

Acceleration=a=\frac{0-4.5}{0.5}

deceleration=a=-9m/s^2

We know that

Force =ma

Using the formula and suppose mass  of my body=m=40 kg

The force exerted by wall on you

Force=40\times (9)=360N

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2 years ago
A baby carriage is sitting at the top of a hill that is 35 m high. The
Lemur [1.5K]
P=M(mass)G(Gravity)H(Height)

Gravity=9.8

M=1.5 G=9.8 H=35

so multiply all

=514.5 potential energy

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