Answer:
1321 N/C
Explanation:
From the question,
Electric Field (E) = Electric Force(F)/Electric Charge(q)
E = F/q............ Equation 1
Given: F = 7.4 μN = 7.4×10⁻⁶ N, q = 5.6 nC = 5.6×10⁻⁹ C
Substitute these value into equation 1
E = ( 7.4×10⁻⁶)/(5.6×10⁻⁹)
E = 1.321×10³ N/C
E = 1321 N/C
Hence the magnitude of the electric field at that location is 1321 N/C
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Answer:
I do not have enough information to tell
Explanation:
This is deduced due to the fact that if the net force due to B and C on A is zero, the charges on B and C could either be positive or negative depending on the charge on A.
