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Marizza181 [45]

2 years ago

7

A golfer hits a stationary golf ball and gives it a velocity of 57.5 m/s. The golf ball has a mass of 0.045 kg. The impact of th

e golf club and the ball
was 0.3 seconds. Calculate the force the golfer puts on the golf ball.

1 answer:

Anton [14]2 years ago

8 0

Answer:

nejdoniwjeiwiwwwwwww

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Nearly all physics problems will use the unit m/s^2 for acceleration. Explain why the seconds are squared. Why isn't the unit gi

sertanlavr [38]

Because acceleration is not speed, and speed is not acceleration.
I'm sure you would not ask "Why isn't temperature given in acres,
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3 years ago

you lift a 30 N crate 2 meters onto a shelf. it takes you 5 seconds to accomplish this. how much gravitional potential energy do

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3 years ago

A river has a steady speed of 0.566 m/s. A student swims upstream a distance of 1.57 km and returns (still swimming) to the star

MArishka [77]

Answer:

3503.72 seconds

819.96 seconds

Explanation:

$V_r$ =Velocity of river = 0.566 m/s

$V_s$ =Velocity of student = 1.17 m/s

Distance to travel = 1.57 km = 1570 m

So,

Time = Distance / Speed

$\frac{1570}{V_s-V_r}+\frac{1570}{V_s+V_r}=t\\\Rightarrow t=\frac{1570}{1.17-0.566}+\frac{1570}{1.17+0.566}\\\Rightarrow t=3503.72\ s$

Time taken by the student to complete the trip is 3503.72 seconds

In still water

$\frac{1570}{V_s}+\frac{1570}{V_s}=t\\\Rightarrow t=\frac{1570}{1.17}+\frac{1570}{1.17}\\\Rightarrow t=2683.76\ s$

The difference in time between moving water and still water is 3503.72-2683.76 = 819.96 seconds

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2 years ago

Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face

Sunny_sXe [5.5K]

Answer:

$\mu = 1.645$

Explanation:

By Snell's law we know at the left surface

$\theta_i = 19^o$

$\theta_r = ?$

$\mu_1 = 1$

$\mu_2 = \mu$

now we have

$1 sin19 = \mu sin\theta_r$

$0.33 = \mu sin\theta_r$

now on the other surface we know that

angle of incidence = $\theta_r'$

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so again we have

$\mu sin\theta_r' = 1 sin90$

so we have

$\theta_r = sin^{-1}\frac{0.33}{\mu}$

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also we know that

$\theta_r + \theta_r' = 49$

$sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49$

By solving above equation we have

$\mu = 1.645$

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3 years ago

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