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dezoksy [38]
3 years ago
13

Which of think following materials is the best is the best choice for an insulating material?

Physics
1 answer:
RSB [31]3 years ago
7 0
You are correct, the answer is C. 

Good insulators are materials that do not allow heat, electricity, light or sound pass through easily. Materials like steel and silver (which are metals) are not good insulators because they make good conductors. They easily allow heat, electricity and the like pass through them. 

Thus, the answer is letter C. Rubber. 
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The position of a ball rolling in a straight line is given by x=2−3.6t+4.4t2, where x is in meters and t in seconds.
kobusy [5.1K]
I'm assuming the question is time it will take for ball to reach ground, if it is then set equation to zero then use the quadratic formula, the possible t value is your answer then
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3 years ago
A simple pendulum consisting of a 1.0m long string and a 0.20kg bob is pulled to the side so that the string makes an angle of 2
gavmur [86]

The definition of energy and simple harmonic motion we can find the result for the point at which the kinetic energy and potential energy are equal is:

         θ = 9.8º

The mechanical energy is the sum of the kinetic energy and the potential energies, in the case that there is no friction, this energy is constant and gives advantage to one of the most important principles of physics.

The kinetic energy is:        K = ½ m v²

The potential energy is:    U = m g (y-y₀)

The mechanical energy is Em = K + U

Where m is mass, v is linear velocity, g is the acceleration of gravity, y height.

The simple pendulum is a simple harmonic system that for small angles has a shape solution.

           θ = θ₀ cos (wt + Ф)

where θ is the angle of motion, w is the angular velocity t time and Ф a phase constant that depends on the initial conditions.

They indicate that the system that has a length of l = 1.0 m, is released at the angle of θ₀ = 20º (π rad / 180º)  = 0.349 rad, remember that in the rotation movement all the angles must be in radian, let's look for the initial constant.

Velocity is defined by the change in position or angles with respect to time.

         w = \frac{d \theta}{dt}  = -θ₀  w sin (wt + Ф)

At the initial movement for time t = 0 the velocity is zero

          0 = - θ₀  w sin Ф

For the equality to be correct, the sine function must be zero, which implies that the phase angle are zero Ф = 0, therefore the solution for the angle and the velocity are:

           θ = θ₀ cos wt

           w = - θ₀  w sin wt

The angular velocity is given by the relation

     w² = g / l

we calculate

      w = \sqrt{\frac{9.8}{1} }  

      w = 3.13 rad / s

let's look for the expression for the energies.

      K = ½ m v²

   

Linear and angular variables are related.

      v = w l

     

We substitute

     K = ½ m l² w²

     

We substitute the expression for the angular velocity.

     K = ½ m l² ( -θ₀ w sin  wt) ²

We look for the potential energy, where we make the initial height zero.

      U = m g θ₀ cos wt

Ask the point where kinetic energy and potential energy  are equal.

          K = U

           ½ m l² θ₀² w² sin² wt = m g θ₀ cos wt

          sin^2 wt = \frac{2 g }{l^2  \ \theta_o \ w^2 } \  cos \ wt

          θ = wt

 

Let's calculate.

         sin^2 \theta = \frac{2 \ 9.8}{ 1^2 \ 0.349 3.13^2 } \  cos \ \theta  

        sin² θ = 5.73  cos θ

The solution of

           θ' = 1.4 + 2π n        n= 0, 1, 2, ...

First occurs for n = 0

           θ = 1.40 rad = 80.2º

This solution is the angle is measured from the horizontal, therefore the angle measured from the vertical corresponds:

          θ = 90- 8.02

          θ = 9.8º

In conclusion using the definition of energy and simple harmonic motion we can find the result for the point at which the kinetic energy and potential energy are equal is:

         θ = 9.8º

Learn more here:  brainly.com/question/17315536

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A 45-year-old woman wants to increase her physical activity to the meet the general guidelines recommended by the United States
lawyer [7]
I would say a. or d.
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3 years ago
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A box is on a ramp that is at angle θ to the horizontal. As θ is increased from zero, and before the box slips, do the following
KIM [24]
The correct answer for the question that is being presented above is this one: "(d) the magnitude of the normal force on the box from the ramp." A box is on a ramp that is at angle θ to the horizontal. As θ is increased from zero, and before the box slips, do the following increase, decrease, or remain the same and  <span> the magnitude of the normal force on the box from the ramp.</span>
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3 years ago
Can someone help plz!?
Verizon [17]
With what? maybe I can help?
5 0
4 years ago
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