Answer:
Part a)
Part b)
Explanation:
Part a)
Constant speed by which the student will run is given as
now after some time if student is going to overtake the position of bus
so here the final positions will be same
so we have
so it is
So student will run the total distance
Part b)
Speed of bus when student reach the bus is given as
Answer:
If x₁=12 cm then k=1.7985 N/m
If x₂=15 cm then k=1.4388 N/m
Explanation:
Hanging mass= 22 g=0.022 kg
Acceleration due to gravity g=9.81 m/s²
If x₁=displacement= 12 cm=0.12 m
k= spring constant
∴k = 1.7985 N/m
If x₂=15 cm=0.15 m
Force of the hanging mass is same however the spring constant will change
∴k = 1.4388 N/m
As the mass is not changing the spring constant has to change. That means that here there are two spring one with k=1.7985 N/m and the other with k= 1.4388 N/m