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katovenus [111]
3 years ago
5

A 1200 Kg car rounds a corner of radius r = 45m. If the coefficient of static friction between the ties and the road is us = 0.8

2, what is the greatest speed the car can have in the corner without skidding?
Physics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

The greatest speed of the car is 19.36m/s

Explanation:

The maximum speed the car will attain without skidding is given by:

F= uN = umg ...eq1

But F = mv^2/r

mv^2/r = umg

Dividing both sides by m, leaves you with:

V= Sqrt(ugr)

Where u = coefficient of static friction

g = acceleration due to gravity

r = raduis

Given:

U = 0.82

r=0.82

g= 9.8m/s

V = Sqrt(0.82 × 9.8 × 45)

V = Sqrt(374.85)

V = 19.36m/s

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Hai vận động viên chạy trên cùng 1 đoạn đường, vận động
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Answer:

Pemain A

Explanation:

Mengingat data berikut;

Kecepatan pemain A = 12 m/s

Kecepatan pemain B = 36 km/h

Untuk menentukan siapa pelari tercepat di antara dua pemain;

Pertama-tama, kita harus mengubah kecepatan menjadi satuan standar pengukuran yang sama.

Jadi, mari kita gunakan pengukuran umum meter per detik.

Konversi:

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36 km/h = 36000/3600

36 km/h = 10 m/s

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Oleh karena itu, dibandingkan dengan kecepatan pemain A; pemain A lebih cepat.

6 0
3 years ago
True or false energy is always lost in a circuit
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7 0
2 years ago
In what direction does the induced current flow in the loop?
bogdanovich [222]

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Clockwise and counter clockwises, depands.

Explanation:

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6 0
3 years ago
The record distance in the sport of throwing cowpats is 81.1 m. This record toss was set by Steve Urner of the United States in
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Answer:

28.2 m/s

Explanation:

The range of a projectile launched from the ground is given by:

d=\frac{v^2}{g}sin 2\theta

where

v is the initial speed

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\theta is the angle at which the projectile is thrown

In this problem we have

d = 81.1 m is the range

\theta=45^{\circ} is the angle

Solving for v, we find the speed of the projectile:

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