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4 years ago

1.After striking the ball, it is important to ______.

Physics

2 answers:

egoroff_w [7]4 years ago

7 0

Answer:

1=A 2=3 3=Badmintion

Explanation:

I think I'm correct on these

mamaluj [8]4 years ago

6 0

1) follow through
2) hand eye coordination
3) basketball

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What is the tension in the string if the turntable is held fixed, with the mass hanging from the pulley (i. e. , the mass is sta

Paladinen [302]

Weight of the mass is the tension in the string if the turntable is held fixed, with the mass hanging from the pulley

Weight is a force that acts at all times on all objects near Earth. The Earth pulls on all objects with a force of gravity downward toward the center of the Earth. Weight (symbolized w ) is a quantity representing the force exerted on a particle or object by an acceleration field, particularly the gravitational field of the Earth at the surface.

The tension force is defined as the force that is transmitted through a rope, string or wire when pulled by forces acting from opposite sides. The tension force is directed over the length of the wire and pulls energy equally on the bodies at the ends.

The direction of tension is the pull which is given the name tension. Thus, the tension will point away from the mass in the direction of the string/rope. In case of the hanging mass, the string pulls it upwards, so the string/rope exerts an upper force on the mass and the tension will be in the upper side.

Tension will act opposite the the weight of the mass attached in order to maintain equilibrium .

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2 years ago

Write an expression for the magnitude of the normal force, fn, acting on the block, in terms of f2 and the other variables of th

mario62 [17]

<span>If the force is fn, then it acting on the block, in the term of f2 and the other variables of the problems. then we assume the surface is rest on it's rigid, then the magnitude of the force is, fn =f2 sin(?) +m g</span>

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4 years ago

UTMSUNG

likoan [24]

Answer:

i think answer id leech because when it move it leave the liner

4 0

3 years ago

a constant current of 3 a for 4 hours is required to charge an automotive battery.if the terminal voltage is 10 t/2 v, where t i

Korvikt [17]

The charge transported as a result of charging is 43200C .

we can note the following data from the statement :

Current (i) = 3A

Time interval (t) = 4 hrs = 14400secs

As we know ,

Current is defined as the rate of flow of the charges between two points when a potential difference is applied between them.

Mathematically , it can be written as

Current(i) = charge (q)/ time(t)

Q = i × t

= 3 × 14400

= 43200 C

By dividing the value of the current passed through the circuit by the time for which the charge is passed gives out the value of the charge passed .

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1 year ago

A pendulum of length L=36.1 cm and mass m=168 g is released from rest when the cord makes an angle of 65.4 degrees with the vert

pychu [463]

(a) -0.211 m

At the beginning the mass is displaced such that the length of the pendulum is L = 36.1 cm and the angle with the vertical is

$\theta=65.4^{\circ}$

The projection of the length of the pendulum along the vertical direction is

$L_y = L cos \theta = (36.1 cm)(cos 65.4^{\circ})=15.0 cm$

the full length of the pendulum when the mass is at the lowest position is

L = 36.1 cm

So the y-displacement of the mass is

$\Delta y = 15.0 cm - 36.1 cm = -21.1 cm = -0.211 m$

(b) 0.347 J

The work done by gravity is equal to the decrease in gravitational potential energy of the mass, which is equal to

$\Delta U = mg \Delta y$

where we have

m = 168 g = 0.168 kg is the mass of the pendulum

g = 9.8 m/s^2 is the acceleration due to gravity

$\Delta y = 0.211 m$ is the vertical displacement of the pendulum

So, the work done by gravity is

$W=(0.168 kg)(9.8 m/s^2)(0.211 m)=0.347 J$

And the sign is positive, since the force of gravity (downward) is in the same direction as the vertical displacement of the mass.

(c) Zero

The work done by a force is:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and the displacement

In this situation, the tension in the string always points in a radial direction (towards the pivot of the pendulum), while the displacement of the mass is tangential (it follows a circular trajectory): this means that the tension and the displacement are always perpendicular to each other, so in the formula

$\theta=90^{\circ}, cos \theta = 0$

and so the work done is zero.

5 0

3 years ago