OH- is the ion that increases the concentration of a base
Answer:
4.17e+22 atoms of tin are present in the cube
Explanation:
We don't require the size of the cube. With the mass and the molar mass of tin = 118.7 amu we can find moles of Tin. As 1 mol = 6.022x10²³ atoms we can find the number of atoms:
<em>Moles Tin:</em>
8.21g * (1mol / 118.7g) = 0.0692 moles Tin
<em>Atoms Tin:</em>
0.0692 moles Tin * (6.022x10²³ atoms / mol) =
<h3>4.17e+22 atoms of tin are present in the cube</h3>
Answer:
The correct answer is 378 g of water
Explanation:
A concentration of 5.50% by mass means that there are 5.50 grams of solute in 100 grams of solution:
5.50 %m/m = 5.50 g solute/100 g solution
If we have 22.0 g of solute (KCl), we found the total mass of solution as follows:
5.50 g KCl ----- 100 g solution
22.0 g KCl ------ X = 22.0 g KCl x 100 g solution/ 5.50 g KCl = 400 g solution
22.0 g KCl/400 g solution = 5.5 g KCl/100 g solution = 5.50 % m/m
This is the total mass of solution (400 g). The mass of water we have to add is the following:
Mass water = 400.0 g solution - 22.0 g KCl = 378.0 g
So, in order to prepare a 5.50% m/m of solution, we have to weight 22.0 g of KCl and to add 378.0 g of water until reaching 400.0 g of total mass solution.
Explanation:
As it is given that the initial concentration of sulfuric acid is 0.010 M.
Hence, the ICE table for first dissociation of sulfuric acid is as follows.
Initial: 0.010 0 0
Change: -0.010 +0.010 +0.010
Equilibrium: 0 0.010 0.010
When second dissociation of sulfuric acid occurs which is partial then the ICE table will be as follows.
Initial: 0.010 0 0.010
Change: -x +x +x
Equilibrium: 0.010 - x x 0.010 + x
Since, it is given that . Hence, formula for is as follows.
x = 0.0045
Hence, by using the equilibrium concentrations from the table and value of x we get the following.
- = x,
= 0.0045 M
- = 0.010 - x
= 0.010 - 0.0045
= 0.0055 M
- = 0.010 + x
= 0.010 + 0.0045
= 0.0145 M