Answer: this is not my own words :)
Learn how factors, such as exposure to the atmosphere, the composition of rock and climate affect the rate of weathering. Weathering is the mechanical or chemical process by which rocks are broken down. The weathering that happens to rocks can be understood by relating it to the digestion of a chocolate chip cookie
One of the factors that affects the rate of weathering is exposure to the atmosphere. ... Another factor that affects the rate of weathering is the composition of rock. Rocks are composed of minerals, which are solid substances found within rocks that have their own distinct chemical composition.
Answer:
Some of the various things that humans do to the environment is pump CO2 into the air with Fossil Fuels and using Power Plants, Cutting down trees make more CO2 which can make the Earth hotter and cause Global Warming. Some natural things that can tend to affect climate can be changes in Volcanic activity, Solar activity with the sun, and Earth's orbit around the sun.
Explanation:
It may seem crazy how Earth's orbit around the sun make climate change, but how else would 4 seasons exist. The orbit tends to be in an oval shape. The top parts of the oval, would represent winter and fall because of the distance between the sun decreases. The closer sides of the oval however, would represent Summer and spring because those are the warmer months and show that Earth is closer to the sun.
Answer:
B₃Si
Explanation:
Let's take break it down. From triboron silicide;
Tri - Three
Triboron - Three boron atoms
Silicide - Silicon (with an -ide suffix)
The formular is given as;
B₃Si
Answer:
I have solution to your question
Answer:
the standard enthalpy of formation of this isomer of C₈H₁₈ (g) = -375 kj/mol
Explanation:
The given combustion reaction
C₈H₁₈ + 25/2 O₂ → 8 CO₂ + 9 H₂O ............................(1)
Heat of reaction or enthalpy of combustion = -5099.5 kj/mol
from equation (1)
ΔH⁰reaction = (Enthalpy of formation of products - Enthalpy of formation of reactants)
Or, - 5099.5 = [8 x ΔH⁰f(CO₂) +9 x ΔH⁰f(H₂O)] - [ΔH⁰f(C₈H₁₈) + ΔH⁰f(O₂)].................................(2)
Given ΔH⁰f(CO₂) = - 393.5 kj/mol & ΔH⁰f(H₂O) = - 285.8 kj/mol and ΔH⁰f(O₂)= 0
Using equation (2)
ΔH⁰f(C₈H₁₈) = -621 kj/mol