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NARA [144]
2 years ago
13

What’s the chemical formula for lithium carbonate

Chemistry
2 answers:
nordsb [41]2 years ago
8 0

Answer:

<h3>Being a science geek the ans is <u><em>Li2CO3</em></u></h3>

Explanation:

Svetllana [295]2 years ago
4 0

Answer:

Li. 2CO. 3

Explanation:

Lithium carbonate is an inorganic compound, the lithium salt of carbonate with the formula Li. 2CO. 3. This white salt is widely used in the processing of metal oxides.

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In which groups of the modern periodic table are very active metals and very active non-metals placed?​
eimsori [14]

Answer:

group 1 and are called Alkali metals. Similarly, very active non-metals are placed in group 17

Explanation:

5 0
2 years ago
Can the work output of an engine be greater than the source of energy.
Arlecino [84]

Answer:

no

Explanation:

the output can never be greater than the input

3 0
2 years ago
I need help with this problem !
Sloan [31]

Answer:

3

Explanation:

7 0
2 years ago
How many moles of water react with 0.946 mol of nitrogen dioxide
VARVARA [1.3K]
<span>the answer is
2.7 moles

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5 0
3 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa
notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4

Finally, the percent yield turns out into:

Y=\frac{1.92g}{7.1g} *100

Y=27.0%

Best regards.

6 0
2 years ago
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