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dangina [55]
4 years ago
7

HELP?!

Physics
2 answers:
svetoff [14.1K]4 years ago
6 0

Answer is the highest temperature, so D

Higher temperatures allow for sound to move faster, since the molecules vibrate faster, sound waves can travel more quickly. The speed of sound in room temperature air is 346 meters per second. This is faster than 331 meters per second, which is the speed of sound in air at freezing temperatures.

Neat little fact: This is also why in the winter when there is snow on the ground, it seems more peaceful and quite. The snow absorbs the sound waves and the temperature makes them not travel as fast, getting more quite as they go.

sertanlavr [38]4 years ago
3 0
Sound will travel fastest in air at 15!
D is the correct answer
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A 2.64-kg copper part, initially at 400 K, is plunged into a tank containing 4 kg of liquid water, initially at 300 K. The coppe
marin [14]

Answer:

a) T_f=305.7049\ K

b) \Delta S=313.51\ J.K^{-1}

Explanation:

Given:

  • mass of copper, m_c=2.64\ kg
  • initial temperature of copper, T_{ic}=400\ K
  • specific heat capacity of copper, c_c=385\ J.kg^{-1}.K^{-1}
  • mass of water, m_w=4\ kg
  • initial temperature of water, T_{iw}=300\ K
  • specific heat capacity of water, c_w=4200\ J.kg^{-1}.K^{-1}

a)

<u>∵No heat is lost in the environment and the heat is transferred only between the two bodies:</u>

Heat rejected by the copper = heat absorbed by the water

2.64\times 385\times (400-T_f)= 4\times 4200\times (T_f-300)

T_f=305.7049\ K

b)

<u>Now the amount of heat transfer:</u>

Q=m_c.c_c.(T_{ic}-T_{f})

Q=2.64\times 385\times (400-305.7049)

Q=95841.5841\ J

∴Entropy change

\Delta S=\frac{dQ}{T}

\Delta S=\frac{95841.5841}{305.7049}

\Delta S=313.51\ J.K^{-1}

5 0
4 years ago
What is general relativity
juin [17]
General relativity is a theory of space and time. The theory was published by Albert Einstein in 1915. The central idea of general relativity is that space and time are two aspects of spacetime. Spacetime is curved when there is gravity, matter, energy, and momentum.
5 0
3 years ago
A fish is able to jump vertically out of the water with a speed of 4.45 m/s. What is the speed of the fish as it passes a point
rjkz [21]

Answer:

Explanation:

given

initial velocity u = 4.45m/s

Height = 0.6m

g = 9.8m/s²

Required

final velocity v

Using the equation of motion;

v² = u²-2gH (upward motion of the fish makes g to be negative)

v² = 4.45²-2(9.8)(0.6)

v² = 19.8025-11.76

v² = 8.0425

v = 2.84 m/s

Hence the speed of the fish as it passes a point 0.6 m above the water is 2.84m/s

To get the time, we will use the formula

v = u - gt

2.84 = 4.45 - 9.8t

2.84-4.45 = -9.8t

-1.61 = -9.8t

t = 1.61/9.8

t = 0.164secs

Hence the time taken is 0.164secs

8 0
3 years ago
Describe effective communication strategies for gathering information, educating patients
timama [110]

Explanation:

Effective communication with patients will enable one to know the needs of the patient better as well as reducing the barriers to understanding each other for both parties.

To be an effective communicator while educating patients, the person must:

  • It is important to establish good rapport with the patient. By so doing they can trust you and let you in. Show empathy. Do not make them feel like you are judging them

  • Use proper body language. Make eye contacts and try to be on the same level as the patient so you can be face to face with them.
  • make the interaction easier for them. You have to keep questions as well as your sentences short and moderate. Stay on topic and always make sure that concepts are clear to them.
  • show respect. try not to speak with commands. Give the patient opportunity to make choices.
  • be patient with them. Due to age or the nature of their illnesses, the patient may be slow in speech or movement. help them to move at their own pace by not rushing them.
  • give them time to respond and ask questions. this will make communication more effective.
  • you cause graphics where necessary or written instructions for the patient.
6 0
3 years ago
The earth has a mass ME = 5.98 · 1024 kg and the moon has a mass MM = 7.36 · 1022 kg. The distance from the center of the earth
ivann1987 [24]

Answer:

2 x 10^20 N

Explanation:

Me = 5.98 x 10^24 kg

Mm = 7.36 x 10^22 kg

r = 3.82 x 10^5 km = 3.82 x 10^8 m

The gravitational force between earth and moon is

F = G Me x Mm / r^2

F = (6.67 x 10^-11 x  5.98 x 10^24 x 7.36 x 10^22) / (3.82 x 10^8 x 3.82 x 10^8)

F = 2 x 10^20 N

6 0
4 years ago
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