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Mice21 [21]
3 years ago
10

The _______ is responsible for determining the frequency of vibration of the air column in the tube within a wind instrument.

Physics
1 answer:
drek231 [11]3 years ago
7 0
<span>Vibrations are small oscillations of the frequency. Sound is produced when something vibrates and that;s whhat music instruments do- they produce sound through vibrations. The resonatpr is device reposnsible for determing the frequency of vibration of teh music instruments.</span>
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3 years ago
A pulsar is a rapidly rotating neutron star. The Crab nebula pulsar in the constellation Taurus has a period of 33.5\times 10^{-
joja [24]

Answer:

5.25\cdot 10^{40} kg m^2/s

Explanation:

The angular momentum of the pulsar is given by:

L=m\omega r^2

where

m=2.8\cdot 10^{30} kg is the mass of the pulsar

r = 10.0 km = 1\cdot 10^4 m is the radius

\omega is the angular speed

Given the period of the pulsar, T=33.5\cdot 10^{-3} s, the angular speed is given by

\omega=\frac{2\pi}{T}=\frac{2 \pi}{33.5\cdot 10^{-3}s}=187.5 rad/s

And so, the angular momentum is

L=m\omega r^2=(2.8\cdot 10^{30}kg)(187.5 rad/s)(1\cdot 10^4 m)^2=5.25\cdot 10^{40} kg m^2/s

8 0
3 years ago
A ski jumper travels down a slope and
AleksandrR [38]

Answer:

304.86 metres

Explanation:

The x and y cordinates are dcos\theta and dsin\theta respectively

The horizontal distance travelled, x=v_{ox}t=dcos\theta

Making t the subject, t=\frac{dcos\theta}{v_{ox}}

Since y=0.5gt^2=dsin\theta, we substitute t with the above and obtain

0.5g(\frac{dcos\theta}{v_{ox}})^2=dsin\theta

Making d the subject we obtain

d=\frac{2v_{ox}^2sin\theta}{gcos^2\theta}

d=\frac{2*30^2sin48}{9.8cos^248}

d=304.8584

d=304.86m

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