What is the name given to group 18 on the periodic table?

Ymorist [56]

Answer:

it shows that co2 is absorbed by the atmosphere.

when the animals respire they produce co2 which is release in atmosphere and in presence of sunlight and chlorophyll the plants manufacturs the food and releases the oxygen in the atmosphere .

hope it helps..

3 0

4 years ago

A jet airliner moving initially at 693 mph (with respect to the ground) to the east moves into a region where the wind is blowin

Nesterboy [21]

Answer:

The new speed of the aircraft with respect to the ground is 1414.3 mph.

Explanation:

Given that,

Angle = 37°

Velocity of jet airliner = 693 mph

Velocity of wind = 798 mph

We know that,

The new velocity of the aircraft with respect to the ground

$v=v_{a}+v_{w}$

We need to calculate the new speed of the aircraft with respect to the ground

Using formula for velocity

$v=\sqrt{(v_{a})^2+(v_{w})^2+2v_{a}v_{w}\cos\theta}$

Put the value into the formula

$v=\sqrt{(693)^2+(798)^2+2\times693\times798\cos37}$

$v=1414.3\ mph$

Hence, The new speed of the aircraft with respect to the ground is 1414.3 mph.

7 0

3 years ago

A parachutist of mass 20.1 kg jumps out of an airplane at a height of 662 m and lands on the ground with a speed of 7.12 m/s. Th

Klio2033 [76]

Answer:

$1.30\cdot 10^5 J$

Explanation:

The energy lost due to air friction is equal to the mechanical energy lost by the parachutist during the fall.

The initial mechanical energy of the parachutist (at the top) is equal to his gravitational potential energy:

$E_i=mgh$

where

m = 20.1 kg is his mass

$g=9.8 m/s^2$ is the acceleration due to gravity

h = 662 m is the initial heigth

The final mechanical energy (at the bottom) is equal to his kinetic energy:

$E_f=\frac{1}{2}mv^2$

where

v = 7.12 m/s is the final speed of the parachutist

Therefore, the energy lost due to air friction is:

$\Delta E=E_i-E_f=mgh-\frac{1}{2}mv^2=(20.1)(9.8)(662)-\frac{1}{2}(20.1)(7.12)^2=1.30\cdot 10^5 J$

4 0

4 years ago

A projectile is fired at an upward angle of 35.6° from the top of a 208-m-high cliff with a speed of 170-m/s. What will be its s

sdas [7]

Answer:

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

Explanation:

Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s

Final horizontal velocity = 138.23 m/s

Considering vertical motion of projectile:

Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = -208 m

We have v² = u² + 2as

Substituting

v² = 98.96² + 2 x -9.81 x -208

v = 117.79 m/s

Final velocity,

$v=\sqrt{138.23^2+117.79^2}=181.61m/s$

$\theta =tan^{-1}\left ( \frac{117.79}{138.23}\right )=40.44^0$

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

5 0

4 years ago

Which of the following pairings are more likely to be held together with the strong nuclear force?

aivan3 [116]

Which of the following pairings are more likely to be held together with the strong nuclear force

Explanation:

1.What does a strong nuclear force do in an atom? It repels electrons from other electrons. It repels protons from other protons. It attracts protons and neutrons.

2.The chain reaction requires both the release of neutrons from fissile isotopes undergoing nuclear fission and the subsequent absorption of some of these neutrons in fissile isotopes.

3.The strong nuclear force holds most ordinary matter together because it confines quarks into hadron particles such as the proton and neutron. In addition, the strong force binds these neutrons and protons to create atomic nuclei.

8 0

3 years ago

What is the name given to group 18 on the periodic table?​

What is the name given to group 18 on the periodic table?