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Paraphin [41]
2 years ago
8

The gravitational force between Earth and the Sun is a two way force. Both the planet and the Sun attract each other. However, E

arth revolves around the Sun rather than the Sun revolving around Earth. What best explain this?

Physics
2 answers:
allsm [11]2 years ago
8 0

Answer:

  • <u>Planets move around the Sun:</u>

Just because due to difference in mass,m. The Sun posses more gravitational power,G and exerts a force,F(g) on the planets to move around it. As the planets do not fall into the star, as they also have a movement upon there very position or spot.

Explanation:

  • <u>Mass,m of the Celestial objects:</u>

There are a number of objects inside the solar system, as the planets, satellites and the Star which is obviously the red giant known as the Sun varies in there mass,m. As the value of the mass,m contributes in creating the amount of gravitational force,G acting on one another.

So, the planets posses an amount of mass in it and contributes to creating the intensity of force that it posses while interacting with one another inside the solar system. While the planet has less weight as compared to the Sun so, they have less gravitational pull with them, but they don't fall into the star just because they also moves side ways in the orbit.

Zinaida [17]2 years ago
7 0
The sun has a greater mass then the earrth
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Explanation:

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your answer will be  8.0±0.3 / 3.5±0.2  units / units²

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A sled is moving at a constant speed down a surface inclined at 45 degrees with the horizontal and travels 30meter in 4 seconds.
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Calculate the wavelength of each frequency of electromagnetic radiation: a. 100.2 MHz (typical frequency for FM radio broadcasti
Natalka [10]

Answer:

a). 100.2 MHz (typical frequency for FM radio broadcasting)

The wavelength of a frequency of 100.2 Mhz is 2.99m.

b. 1070 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)

The wavelength of a frequency of 1070 khz is 280.3 m.

c. 835.6 MHz (common frequency used for cell phone communication)

The wavelength of a frequency of 835.6 Mhz is 0.35m.

Explanation:

The wavelength can be determined by the following equation:

c = \lambda \cdot \nu  (1)

Where c is the speed of light, \lambda is the wavelength and \nu is the frequency.  

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave.

<em>a). 100.2 MHz (typical frequency for FM radio broadcasting)</em>

Then, \lambda can be isolated from equation 1:

\lambda = \frac{c}{\nu} (2)

since the value of c is 3x10^{8}m/s. It is necessary to express the frequency in units of hertz.

\nu = 100.2 MHz . \frac{1x10^{6}Hz}{1MHz} ⇒ 100200000Hz

But 1Hz = s^{-1}

\nu = 100200000s^{-1}

Finally, equation 2 can be used:

\lambda = \frac{3x10^{8}m/s}{100200000s^{-1}}

\lambda = 2.99 m

Hence, the wavelength of a frequency of 100.2 Mhz is 2.99m.

<em>b. 1070 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)</em>

<em> </em>

\nu = 1070kHz . \frac{1000Hz}{1kHz} ⇒ 1070000Hz

But  1Hz = s^{-1}

\nu = 1070000s^{-1}

Finally, equation 2 can be used:

\lambda = \frac{3x10^{8}m/s}{1070000s^{-1}}

\lambda = 280.3 m

Hence, the wavelength of a frequency of 1070 khz is 280.3 m.

<em>c. 835.6 MHz (common frequency used for cell phone communication) </em>

\nu = 835.6MHz . \frac{1x10^{6}Hz}{1MHz} ⇒ 835600000Hz

But  1Hz = s^{-1}

\nu = 835600000s^{-1}

Finally, equation 2 can be used:

\lambda = \frac{3x10^{8}m/s}{835600000s^{-1}}

\lambda = 0.35 m

Hence, the wavelength of a frequency of 835.6 Mhz is 0.35m.

6 0
3 years ago
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