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3 years ago

Solve by substitution y=6x-11 -2x-3y=-7

2 answers:

6 0

$y=6x-11\\
-2x-3y=-7\\\\\
substitute \ y=6x-11\ into\ equation\\\\\
-2x-3(6x-11)=-7\ \ \ \ |omit\ the\ bracket\\\\
-2x+18x+33=-7\\\\
16x+33=-7 \ \ \ \ | subtract\ 33\\\\
16x=-40\ \ \ | divide\ by\ 16\\\\
x=-\frac{40}{16}=-\frac{5}{2}\\\\
y=6x-11=6*(-\frac{5}{2})-11=-15-11=-26\\\\Solution:\\ \left \{ {{y=-26} \atop {x=-\frac{5}{2}}} \right.$

Neporo4naja [7]3 years ago

5 0

So you substitute y=6x-11 into -2x-3y=-7

-2x-3(6x-11)=-7
add like terms
-20x+33=-7
subtract 33 from both sides
-20x=-40
multiply by -1
20x=40
divide both sides by 20
x=2

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3 years ago

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Find the 44th percentile, P44, from the following data! pls help

irina [24]

Answer:

$P_{44} = 29.9$

Step-by-step Explanation:

The 44th percentile, $P_{44}$ , of the given data can be calculated using the kth formula for percentile given as:

$i = \frac{k}{100}(n + 1)$

where,

i = the ranking or the position of the percentile = ?

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n = total number of the given data values = 23

Plug in the values into the formula to find "i"

$i = \frac{44}{100}(23 + 1)$

$i = \frac{44}{100}(24)$

$i = \frac{1,056}{100}$

$i = 10.56$

Since "I", 10.56, is not an integer, round the number down, and round it up to the nearest integer, then look for the position each occupy in the ordered data set, and find their average.

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The data occupying the 10th position on the data set = 28.7

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3 years ago

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well this is from google and just so u know the letters stand for the names

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3 years ago

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vlada-n [284]

Answer:

$D=3.5\ gr/cm^3$

Step-by-step explanation:

<u>Density</u>

The density of an object of mass m and volume V is given by

$\displaystyle D=\frac{m}{V}$

It can be expressed in common units like $gr/lt, Kg/m^3, gr/cm^3$ or any other combination of proper mass [M] by volume [V] units.

The data provided in the question is

$m=200\ mg = 0.2\ gr$

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Thus, the measured density is

$\displaystyle D=\frac{0.2\ gr}{0.057 \ cm^3}$

$\boxed{D=3.5\ gr/cm^3}$

We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.

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3 years ago