Question

Solve by substitution y=6x-11 -2x-3y=-7

Answer 1

$y=6x-11\\ -2x-3y=-7\\\\\ substitute \ y=6x-11\ into\ equation\\\\\ -2x-3(6x-11)=-7\ \ \ \ |omit\ the\ bracket\\\\ -2x+18x+33=-7\\\\ 16x+33=-7 \ \ \ \ | subtract\ 33\\\\ 16x=-40\ \ \ | divide\ by\ 16\\\\ x=-\frac{40}{16}=-\frac{5}{2}\\\\ y=6x-11=6*(-\frac{5}{2})-11=-15-11=-26\\\\Solution:\\ \left \{ {{y=-26} \atop {x=-\frac{5}{2}}} \right.$

Answer 2

So you substitute y=6x-11 into -2x-3y=-7

-2x-3(6x-11)=-7
add like terms
-20x+33=-7
subtract 33 from both sides
-20x=-40
multiply by -1
20x=40
divide both sides by 20
x=2