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wel
3 years ago
15

A dog starts from rest to chase after a ball. If the dog reaches a maximum speed of 5.4 m/s in 8.2 seconds, what is the accelera

tion of the dog?
Physics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

0.66 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0

Final velocity (v) = 5.4 m/s

Time (t) = 8.2 secs

Acceleration (a) =....?

The acceleration of the dog can be obtained as follow:

v = u + at

5.4 = 0 + a × 8.2

5.4 = 8.2a

Divide both side 8.2

a = 5.4/8.2

a = 0.66 m/s²

Therefore, the acceleration of the dog is 0.66 m/s².

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valkas [14]
<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size a of its orbit.

This Law is originally expressed as follows:

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a=3.4(10)^{6}m  is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)

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T=\sqrt{\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(6.39(10)^{23}kg)}(3.4(10)^{6}m)^{3}}    (3)

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T=3403.1099s=56.718min    This is the orbital period of a spacecraft in a low orbit near the surface of mars

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