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wel
2 years ago
15

A dog starts from rest to chase after a ball. If the dog reaches a maximum speed of 5.4 m/s in 8.2 seconds, what is the accelera

tion of the dog?
Physics
1 answer:
Lelechka [254]2 years ago
4 0

Answer:

0.66 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0

Final velocity (v) = 5.4 m/s

Time (t) = 8.2 secs

Acceleration (a) =....?

The acceleration of the dog can be obtained as follow:

v = u + at

5.4 = 0 + a × 8.2

5.4 = 8.2a

Divide both side 8.2

a = 5.4/8.2

a = 0.66 m/s²

Therefore, the acceleration of the dog is 0.66 m/s².

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I. What is the initial velocity of the car?
qaws [65]

Answer:

I. 0 m/s

II. 20 m/s

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Explanation:

I. Determination of the initial velocity.

From the diagram given above,

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II. Determination of the maximum velocity attained.

From the diagram given above, we can see clearly that the maximum velocity is 20 m/s.

III. Determination of the part of the graph that represents zero acceleration.

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2. Two long parallel wires each carry a current of 5.0 A directed to the east. The two wires are separated by 8.0 cm. What is th
Gre4nikov [31]

Answer:

The magnitude of magnetic field at given point = 5.33 × 10^{-5} T

Explanation:

Given :

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From biot savert law,

We know the magnetic field due to long parallel wires.

⇒ B = \frac{\mu_{0}i }{2\pi R}

Where B = magnetic field due to long wires, \mu_{0} = 4\pi \times10^{-7}, R = perpendicular distance from wire to given point

From any one wire R_{1}  = 5 cm, R_{2}  = 3 cm

so we write,

∴ B = B_{1} + B_{2}

 B = \frac{\mu_{0} i}{2\pi R_{1} } +  \frac{\mu_{0} i}{2\pi R_{2} }

 B =\frac{ 4\pi \times10^{-7} \times5}{2\pi } [\frac{1}{0.03} + \frac{1}{0.05} ]

 B = 5.33\times10^{-5}  T

Therefore, the magnitude of magnetic field at given point = 5.33\times10^{-5} T

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3 years ago
Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 m apart and are emitting 1700-hz sound waves into a room where the
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Given the following in the problem:

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