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malfutka [58]
3 years ago
9

PLS HELP BEING TIMED!!!

Physics
2 answers:
Elodia [21]3 years ago
7 0

Answer:

K_{i}+U_{g,i} = K_{f}+U_{g,f}

Explanation:

A closed system is a system where exists energy interactions with surroundings, but not mass interactions. If we neglect any energy interactions from boundary work, heat, electricity, magnetism and nuclear phenomena and assume that process occurs at steady state and all effects from non-conservative forces can be neglected, then the equation of energy conservation is reduce to this form:

\Delta K +\Delta U_{g} = 0 (1)

Where:

\Delta K - Change in kinetic energy of the system, measured in joules.

\Delta U_{g} - Change in gravitational potential energy of the system, measured in joules.

If we know that \Delta K=K_{i}-K_{f} and \Delta U_{g} = U_{g,i}-U_{g,f}, then we get the following equation:

K_{i}+U_{g,i} = K_{f}+U_{g,f} (2)

Where i and f stands for initial and final states of each energy component.

Hence, the right answer is K_{i}+U_{g,i} = K_{f}+U_{g,f}

Rzqust [24]3 years ago
3 0

Answer:

KEi + PEi = KEf + PEf

Explanation

right on edge 2020

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A block of wood has density 0.500 g/cm3 and mass 2 000 g. It floats in a container of oil (the oil's density is 0.750 g/cm3). Wh
Gennadij [26K]

Answer:

2,666.67cm^3

Explanation:

All we need to do in this problem is divide the mass of the wooden block to the oil's density.

2000/0.750 ≈ 2,666.67cm^3

Best of Luck!

6 0
2 years ago
Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 11.7 revolutions/s. Find the linear speed v
Eduardwww [97]

Answer:

The linear speed of the car, v, is 24.26 m/s

Explanation:

Given;

radius of the car's tire, r = 0.330 m

angular speed of the car, ω = 11.7 revolutions/s

The angular speed of the car in radian per second:

\omega = 11.7 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 73.523 \ rad/s

The linear speed of the car, v, is calculated as;

v = ωr

v = 73.523 rad/s  x  0.33 m

v = 24.26 m/s

Therefore, the linear speed of the car, v, is 24.26 m/s

7 0
3 years ago
The work done when a force moves a body through a distance of 15m is 1800j. What is the value of the force applied
Leviafan [203]

Answer:

120

Work :

W = Fd (work = force x distance)

Force :

F = W/d

Distance :

d = W/F

7 0
3 years ago
On a safari, a team of naturalists sets out toward a research station located 4.63 km away in a direction 38.7 ° north of east.
Talja [164]

This is a vector subraction problem.

5 0
3 years ago
Read 2 more answers
A satellite in outer space is moving at a constant velocity of 20.5 m/s in the +y direction when one of its on board thruster tu
Katyanochek1 [597]

Answer:

a)  V_f = 25.514 m/s

b)  Q =53.46 degrees CCW from + x-axis

Explanation:

Given:

- Initial speed V_i = 20.5 j m/s

- Acceleration a = 0.31 i m/s^2

- Time duration for acceleration t = 49.0 s

Find:

(a) What is the magnitude of the satellite's velocity when the thruster turns off?

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.

Solution:

- We can apply the kinematic equation of motion for our problem assuming a constant acceleration as given:

                                   V_f = V_i + a*t

                                   V_f = 20.5 j + 0.31 i *49

                                   V_f = 20.5 j + 15.19 i

- The magnitude of the velocity vector is given by:

                                   V_f = sqrt ( 20.5^2 + 15.19^2)

                                   V_f = sqrt(650.9861)

                                  V_f = 25.514 m/s

- The direction of the velocity vector can be computed by using x and y components of velocity found above:

                                 tan(Q) = (V_y / V_x)

                                 Q = arctan (20.5 / 15.19)

                                 Q =53.46 degrees

- The velocity vector is at angle @ 53.46 degrees CCW from the positive x-axis.

4 0
3 years ago
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