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liq [111]
3 years ago
14

Simplify (15x^2 - 24x + 9) divided (3x - 3) =

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0
Your answer would be 5x-3
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Hello there!
otez555 [7]

Answer:

24  Domain: s>=2  or s<=-2

25. 3x^2 +14x +10

26. x^2 -2x+5  

Step-by-step explanation:

24.  Domain is the input or s values

square roots must be greater than or equal to zero

s^2-4 >=0

Add 4 to each side

s^2 >=4

Take the square root

s>=2  or s<=-2


25.  f(g(x))  stick g(x) into f(u) every place you see a u

f(u) = 3u^2 +2u-6

g(x) = x+2

f(g(x) = 3(x+2)^2 +2(x+2) -6

Foil the squared term

       = 3(x^2 +4x+4) +2x+4-6

Distribute

       = 3x^2 +12x+12 +2x+4-6

Combine like terms

   =3x^2 +14x +10


26 f(g(x))  stick g(x) into f(u) every place you see a u

f(u) = u^2+4

g(x) = x-1

f(g(x) = (x-1)^2 +4

Foil the squared term

         = (x^2 -2x+1) +4

         = x^2 -2x+5  

7 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
Help and i will give brainiest if you answer them all if random will report
Stels [109]

Answer:

first one is a and the second one is c

6 0
2 years ago
Read 2 more answers
What is the area of this triangle?
dsp73

Answer:60

Step-by-step explanation:

a=13 b=13 c=10

Perimeter of =a+b+c

perimeter of =13+13+10

Perimeter of =36

S=36 ➗ 2

S=18

Area=√s(s-a)(s-b)(s-c)

Area=√18(18-13)(18-13)(18-10)

Area=√18(5)(5)(8)

Area=√(3600)

Area of =60

4 0
3 years ago
I NEED HELP, THIS IS DUE BY TONIGHT
finlep [7]
Well the minutes are 198 still working on the rest
4 0
3 years ago
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