Answer: J(25) + JS(5) = 30
Step-by-step explanation:
J = Jason
JS = Jason Sister.
Answer:
-14/5
Step-by-step explanation:
-11 - 3= -14 and the denominator stays the same.
45m 6m^5 usually helps to list the factors of each number first,
1x45=453x15=455x9=45
1x6=62x3=6
so the biggest number that fits into both would be 3, and the biggest amount you can take of any variable would be the amount of that lowest variable. when given an "m" and "m^5", you can only take out one "m", because when m÷m=1, that means you can't take any more "m's" out. if it were m^2 and m^5 you would take out m^2 :)
so your final answer would be"3m" and if you were taking it out of an equation (if you had 45m+/-6m^6)would look like 3m(15+/-2m^4
I suspect you meant
"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"
• Count the multiples of 10:
⌊100/10⌋ = ⌊10⌋ = 10
• Count the multiples of 7:
⌊100/7⌋ ≈ ⌊14.2857⌋ = 14
• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and
⌊100/70⌋ ≈ ⌊1.42857⌋ = 1
(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)
Then using the inclusion/exclusion principle, there are
10 + 14 - 1 = 23
numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.
