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Answer: The mass is 3.58*10^-2 g
Explanation: In order to calculate the mass corresponding to of a small spherical shot of copper inside a graduate cylinder with water we have considered the total volume of water incresed after put the cooper pieces.
In this sense the total increased volume of water is equal to the volume of the 125 small spherical shot of copper so we have the following:
0.5 mL= 125* volume of each piece of cooper=125*Vcopper
Vcooper=0.5/125 mL=5*10^-7 m^3/125=4*10^-9 m^3
Therefore the mass corresponding to each copper piece is equal to:
density of copper* Vcopper piece= 8960 Kg/m^3*4*10^-9 m^3=3.58*10^-5 Kg = 3.58*10^-2 g
The answer is B. <span>The distance must be one-third the original distance.</span>
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Answer:
Explanation:
Mass of gold deposited = 0.5 g
Molar mass of gold = 197 g/mol
Time, t = 6 hours
= 6 × 3600
= 12600 s
Number of moles = mass/molar mass
= 0.5/197
= 0.00254 mole
Assuming
Au --> Au+ + e-
Faraday constant = 9.65 x 104 C mol-1
Q = 96500 × 0.00254
= 244.924 C
Q = I × t
I = 244.924/12600
= 0.011 A
= 11.34 mA.