3 years ago

2. A solid plastic cube of side 0.2 m is submerged in a liquid of density 0.8 hgm calculate the

Physics

1 answer:

kotegsom [21]3 years ago

3 0

Answer:

vpg = 0.064 N

Explanation:

Upthrust = Volume of fluid displaced

upthrust liquid on the cube g=10ms−2

vpg =0.2 x 0.2 x 0.2 x0.8 x 10= 0.064N

vpg = 0.064 N

hope it helps.

You might be interested in

9. A soft drink distibutor drove west 11 km from Minnehaha to Nut Plains. She then turned around and drove back east for 209 km

guajiro [1.7K]

Answer:

220km

Explanation:

Given parameters:

Distance traveled from Minnehaha to Nut Plains = 11km

Distance traveled to Dover = 209km

Unknown:

The distance the soft drink distributor traveled = ?

Solution:

To solve this problem, we must understand that distance is the total length of path covered in a journey.

So;

Distance = 209km + 11km = 220km

The soft drink distributor covered 220km

3 0

2 years ago

While riding a skateboard, Nina ran into a rough patch of pavement, but she thought she could ride right over it. Instead, the s

Jet001 [13]

Answer:

inertia

Explanation:

While riding a skateboard, Nina ran into a rough patch of pavement, but she thought she could ride right over it. Instead, the skateboard stopped but Nina didn't. Her (Blank) kept her moving forward, so she fell off the skateboard.inertia

3 0

3 years ago

Read 2 more answers

Electric kettle with the resistance of 20-02.is used-to-heat:4 kg of water. If

jeka94

The guy that answered this is fake and he’s doing it for free points so
Just repost it and hope he doesn’t find it

5 0

2 years ago

True or false? Most forces occur in pairs, such as when

statuscvo [17]

This is TRUE everything has a action the force from your feet pushes and the floor pushes back

8 0

3 years ago

A spring stretches 0.1 m when a 0.5 kg mass is hung from it. The spring is now oriented horizontally with the mass attached to o

monitta

Answer:

1.98 rad/s

Explanation:

Given that a spring stretches at a distance $x_0$ 0.1 m when a mass of 0.5 kg is attached to it.

The angular velocity $w = \sqrt {\frac{k}{m}} = \sqrt{\frac{g}{x_0}}$

$\omega = \sqrt{\frac{g}{x_0}}\\\\\omega = \sqrt{\frac{9.81}{0.1}}\\\\\omega = 9.9 \ rad/s$

If it is stretched 0.2 m from the equilibrium length; we have:

The maximum velocity v = 0.2 × 9.9

v = 1.98 rad/s

Therefore; the maximum velocity of the mass = 1.98 rad/s

5 0

3 years ago