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Feliz [49]
2 years ago
12

A cylinder 0.170 m in diameter rotates in a lathe at 530 rpm . what is the tangential speed of the surface of the cylinder?

Physics
1 answer:
Ad libitum [116K]2 years ago
8 0
Diameter = 0.170 meter
Circumference = 0.170 π meters

530 rpm = 530 circumferences / minute

               =  (530 x 0.170 π meters) / minute

               =      283.06 meter.minute

               =        4.72 meters/second
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A car moves in a circular motion and it is subject to a centripetal acceleration of 24 m/s2. If the radius of the circular path
Softa [21]

Answer:

Explanation:

Centripetal acceleration is given by:

a_{c} = v^{2}/r

Thus, centripetal acceleration is inversely proportional to the radius. Thus, when radius will double, the centripetal acceleration will be halved.

3 0
3 years ago
A circular bird feeder 19.0 cm in radius has rotational inertia 0.130 kg·m2. It's suspended by a thin wire and is spinning slowl
soldi70 [24.7K]

Answer:

N₂=20.05 rpm

Explanation:

Given that

R= 19 cm

I=0.13 kg.m²

N₁ = 24.2 rpm

\omega_1=\dfrac{2\pi \times 24.2}{60}\ rda/s

ω₁= 2.5 rad/s

m= 173 g = 0.173 kg

v=1.2 m

Initial angular momentum L₁

L₁ =  Iω₁  - m v r       ( negative sign because bird coming opposite to motion of the wire motion)

Final linear momentum L₂

L₂=  I₂ ω₂

 I₂ = I + m r²

The is no any external torque that is why angular momentum will be conserve

L₁ = L₂

Iω₁  - m v r =  I₂ ω₂

Iω₁  - m v r =  ( I + m r²) ω₂

Now by putting the all values

Iω₁  - m v r =  ( I + m r²) ω₂

0.13 x 2.5 - 0.173 x 1.2 x 0.19 =  ( 0.13 + 0.173 x  0.19²) ω₂

0.325  - 0.0394 = 0.136 ω₂

ω₂ = 2.1 rad/s

\omega_2=\dfrac{2\pi \times N_2}{60}

N₂=20.05 rpm

3 0
3 years ago
A force of 825 N is needed to push a car across a parking lot. Two students push a car 35 m. How much total work is done?
MaRussiya [10]
<h2>Answer :</h2><h2 />

Work is the amount of energy transferred. As per the formula

Work = Force x Distance [moved toward the direction of the force]

So as per the formula

<u>Solution : </u>

Force = 825 N

Distance = 35 m

Work = 825 (n) x 35 (m)

Work = 28875 Joules

<h2 />
6 0
3 years ago
In the expression 3x2y + 4x – 5x2y, are the terms 3x2y and –5x2y like terms? Explain by providing support for your answer.
Zanzabum
Https://www.cymath.com/answer?q=%205%2B4i%2F6%2B8i
this site can help you 
3 0
3 years ago
Read 2 more answers
Find the initial velocity of a car which stops in 10sec, after applying brakes at the rate of 2m/s²
Dennis_Churaev [7]

Answer:

20\ m/s

Explanation:

Since we are given time, acceleration, and final velocity, we can use the following formula to find the initial velocity:

v_f = v_i + at

Our given values:

v_f = 0\\a = -2\\t = 10\\

<em>Acceleration is negative because the car is slowing down.</em>

Add the values to the formula, and solve for v_i:

v_f = v_i + at\\0 = v_i + (-2)(10)\\0 = v_i -20\\20 = v_i

7 0
2 years ago
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