Answer:
Final velocity of ball = 20 m/s
Explanation:
Given:
Height when ball released = 20meter
Find;
Time taken to fall
Final velocity of ball
Computation:
Initial velocity of ball = 0 m/s
Acceleration due to gravity = 10 m/s²
Using equation of motion;
S = ut + (1/2)(g)(t²)
20 = (0)(t) + (1/2)(10)(t²)
20 = 5(t²)
(t²) = 20 / 5
(t²) = 4
Time taken to fall = 2 second
V = u + at
V = 0 + (10)(2)
Final velocity of ball = 20 m/s
Explanation:
Below is an attachment containing the solution.
C.) Year
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Answer:
The height of the pyramid is approximately 104 Ft. See the graphic attached.
Explanation:
First, you have to plot to realize that you have two rectangle triangles, formed by the different elevation points of view. From there you can have a system of two equations, with two unknown values.
Equation (1)
![tan 37^{o}50'= \frac{Ph}{x} \\\\Ph=tan 37^{o}50' x= 0.7766 x](https://tex.z-dn.net/?f=tan%2037%5E%7Bo%7D50%27%3D%20%5Cfrac%7BPh%7D%7Bx%7D%20%5C%5C%5C%5CPh%3Dtan%2037%5E%7Bo%7D50%27%20%20x%3D%200.7766%20x)
Equation (2)
![tan 18^{o}10'=\frac{Ph}{x+183} \\\\Ph=[tan 18^{o}10'][x+183]=[0.3281][x+183]](https://tex.z-dn.net/?f=tan%2018%5E%7Bo%7D10%27%3D%5Cfrac%7BPh%7D%7Bx%2B183%7D%20%5C%5C%5C%5CPh%3D%5Btan%2018%5E%7Bo%7D10%27%5D%5Bx%2B183%5D%3D%5B0.3281%5D%5Bx%2B183%5D)
Matching (1) and (2)
![0.7766 x=0.3281(x+183)\\\\(0.7766-0.3281)x=60.05\\\\x=\frac{60.05}{0.4485} =133.89ft](https://tex.z-dn.net/?f=0.7766%20x%3D0.3281%28x%2B183%29%5C%5C%5C%5C%280.7766-0.3281%29x%3D60.05%5C%5C%5C%5Cx%3D%5Cfrac%7B60.05%7D%7B0.4485%7D%20%3D133.89ft)
replacing x value in (1)
![Ph=0.7766*133.89=103.9789\\Ph = 104 ft](https://tex.z-dn.net/?f=Ph%3D0.7766%2A133.89%3D103.9789%5C%5CPh%20%3D%20104%20ft)