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yan [13]
3 years ago
14

A harmonic oscillator begins to vibrate with an amplitude of 1.6 m, but after a time of 1.5 minutes, the amplitude has dropped t

o 0.80 m. What is the time constant of the damping of this oscillator?
Physics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

time constant of the damping 130 seconds

Explanation:

given data

amplitude A1 = 1.6 m

time t = 1.5 min = 90 sec

amplitude A2 = 0.80 m

to find out

time constant of the damping

solution

we know here that maximum amplitude at time t is express as

A2 = A1 × ee^{\frac{-t}{b} }       .............a

here b is time constant

so b will be from equation 1

b = \frac{t}{ln(\frac{A1}{A2} )}       ............b

put here all value top find b

b = \frac{90}{ln(\frac{1.6}{0.80} )}  

b =  \frac{90}{ln(2)}

b = 129.84

so time constant of the damping 130 seconds

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